Answer:5
μM is the initial concentration of the substrate, [S], used in the reaction.
Explanation:
Michaelis–Menten 's equation:
v = rate of formation of products = μM/s
[S] = Concatenation of substrate = ?
= Michaelis constant = 15.0 μM
= Maximum rate achieved
= Catalytic rate of the system = 221
= Initial concentration of enzyme. =0.0100 μM
On substituting all the given values:
μM
μM is the initial concentration of the substrate, [S], used in the reaction.
Answer:
-27.2 kJ
Explanation:
We can use the heat-transfer formula. Recall that:
Where <em>m</em> is the mass, <em>C</em> is the substance's specific heat, and Δ<em>T</em> is the change in temperature.
Hence substitute:
Therefore, the cooling of the water <em>released</em> about 27.2 kJ of heat.
<span>6s²4f¹⁴5d¹⁰6p²
6 shows that the element is in the 6 period,
6p² shows that the element is in the 14th group. (1 and 2 groups have s -electrons as last ones, 13 group has s²p¹, and 14 group has s²p²)
The element is Pb.
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Answer:
Pull
Explanation:
The higher the effective nuclear charge, the more the nucleus will be gaining protons. This process makes the electrons to be drawn closer to the positive charge of
the nucleus.
Thus, it leads to a greater pull exerted by the nucleus on the added electrons.
Answer:
1.89 g CaCO₃
Explanation:
You will have to use stoichiometry for this question. First, look at the chemical equation.
Na₂CO₃ + CaCl₂ ==> 2 NaCl + CaCO₃
From the above equation, you can see that for one mole of Na₂CO₃, you will produce one mole of CaCO₃. This means that however many moles of Na₂CO₃ you have in the beginning, you will have the same amount of moles of CaCO₃, theoretically speaking.
So, convert grams to moles. You should get 0.0189 mol Na₂CO₃. This means that you will get 0.0189 mol CaCO₃. I'm not sure what units you want the answer in, but I'm going to give it in grams. Convert moles to grams. Your answer should be 1.89 g.