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spin [16.1K]
3 years ago
15

WILL GIVE BRAINLIEST!! FINALS!

Mathematics
1 answer:
GenaCL600 [577]3 years ago
3 0
Factor completely x³ + 6x² - 3x – 18
- 6 + 6( - 6)^{2}  - 3( - 6) - 18 \\  - 6 +6 \times 6 ^{2}  + 18 - 18 \\  - 6 + 6 ^{3}  + 18 - 18 \\  - 6 + 216 \\ 210
with a root of x = -6

the answer is 210


You might be interested in
Write a multiplication equation to represent each division equation 50 divided by 10 equals 5
ASHA 777 [7]

Answer: this questions kind of confusing, but my guess is:

10x5=50 Becuase that's the same thing as saying 50/10 =5

Step-by-step explanation:

5 0
3 years ago
What expression can be used to convert 80 US dollars to australian dollars
Lana71 [14]
1 US dollar =1.31 Australian dollar
80 US dollar = x dollar
CrossMultiply
X = 140.8 dollar
6 0
3 years ago
Help someone how do you solve this
Flauer [41]

Answer:

a = 10/3

Step-by-step explanation:

This can be written as:

x^{2} (x^{4})^{1/3}  = x^{a}

Anything to the power of 1/3 means to find the cube root. We can simplify this to:

x^{2} (x^{4/3}) = x^{a}

I just multiplied 4 and 1/3 (because of the second index law (a^{m})^{n}  = a^{mn}). Now, we can add the powers because the bases are the same and we are multiplying (first index law):

x^{10/3} = x^{a}

a = 10/3

Hope this helps!

5 0
2 years ago
Carry out three steps of the Bisection Method for f(x)=3x−x4 as follows: (a) Show that f(x) has a zero in [1,2]. (b) Determine w
ELEN [110]

Answer:

a) There's a zero between [1,2]

b) There's a zero between [1.5,2]

c) There's a zero between  [1.5,1.75].

Step-by-step explanation:

We have f(x)=3^x-x^4

A)We need to show that f(x) has a zero in the interval [1, 2]. We have to see if the function f is continuous with f(1) and f(2).

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(2)=3^2-(2)^4=9-16=(-7)

We can see that f(1) and f(2) have opposite signs. And f(1)>f(2) and the function is continuous, this means that exists a real number c between the interval [1,2] where f(c)=0.

B)We have to repeat the same steps of A)

For the subinterval [1,1.5]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1) and f(1.5) have the same signs, this means there's no zero in the subinterval [1,1.5].

For the subinterval [1.5,2]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.5) and f(2) have opposite signs, this means there's a zero between the subinterval [1.5,2].

C)We have to repeat the same steps of A)

For the subinterval [1,1.25]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5

f(1) and f(1.25) have the same signs, this means there's no zero in the subinterval [1,1.25].

For the subinterval [1.25,1.5]:

f(x)=3^x-x^4\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1.25) and f(1.5) have the same signs, this means there's no zero in the subinterval [1.25,1.5].

For the subinterval [1.5,1.75]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)

f(1.5) and f(1.75) have opposite signs, this means there's a zero between the subinterval [1.5,1.75].

For the subinterval [1.75,2]:

f(x)=3^x-x^4\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.75) and f(2) have the same signs, this means there isn't a zero between the subinterval [1.75,2].

The graph of the function shows that the answers are correct.

6 0
3 years ago
A circular mirror is surrounded by a square metal frame. The radius mirror is 6x the side length of the medal frame is 18x. What
wolverine [178]

Answer:

Step-by-step explanation:

Given:

Radius of circular mirror, r = 6x

Length of metal frame, l = 18x

Area of square, As = l^2

Area of square = 18x × 18x

= 324 x^2.

Area of circular mirror, Ac = pi × r^2

= π × (6x)^2

= 36π x^2.

The expression for the area of the frame is subtracting the mirror from the metal frame = As - Ac

= 324x^2 - 36πx^2

= 36x2 (9 - π).

4 0
3 years ago
Read 2 more answers
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