A ball is gently dropped from a height of 20 m. If its velocity Increases uniformly at the rate of 10 m s2, with what velocity w
ill it strike the ground? After what time will it strike the ground?
2 answers:
Answer:
20 m/s
Explanation:
Height (s)= 20m
acceleration (a) = 10 m/s^2
v=?
we know,
V^2= U^2 + 2as. (U is initial velocity)
or,. V^2 = 0 + 2 × 10 × 20
or, V^2 = 400
or,. V = 20 m/s
Explanation:
Initial Velocity of the ball (u) = 0
Distance or height of fall (s) = 20 m
Downward acceleration (a) = 10 m s-2
As we know
2as = v2 – u2
v2 = 2as + u2
v2 = (2 x 10 x 20 ) + 0
v2 = 400
Final velocity of ball (v) = 20 ms-1
t = (v – u)/a
Time taken by the ball to strike (t) = (20 – 0)/10
t = 20/10
t = 2 seconds
The final velocity with which the ball will strike the ground is (v) = 20 ms-1
The time it takes to strike the ground (t) = 2 seconds
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