make a sketch showing the direction of the magnetic field from the solenoid. on your sketch, label the induced north magnetic po
1 answer:
A coil of wire with electric current running through it is a solenoid. A solenoid is depicted in the Figure below.
A magnetic field with north and south poles, similar to a bar magnet, is created as current flows through the coil. The magnetic field inside the solenoid has a parallel, linear pattern. A solenoid's magnetic field moves from its north pole to its south pole in one direction only. The north and south poles of a solenoid can be determined using the clock face rule. A solenoid is enclosed by a magnetic field and has north and south magnetic poles similar to a bar magnet.
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Answer:
The magnitude of the electric flux is
Explanation:
Given that,
Electric field = 2.35 V/m
Angle = 25.0°
Area
We need to calculate the flux
Using formula of the magnetic flux
Where,
A = area
E = electric field
Put the value into the formula
Hence, The magnitude of the electric flux is
Answer:
987 joules, 3.01s
Explanation:
(A)
from the attached diagram
net force, Fnet, pulling the crate up the ramp is given by
Fnet = FcosФ - WsinФ - Fr
where FcosФ is the component of horizontal force 290N resolved parallel to the plane
WsinФ = mgsinФ = component of the weight of the crate resolved parallel to the plane
Fr = constant opposing frictional force
Fnet = 290cos34⁰ - 20 × 9.8 × sin34° - 65
Fnet = 240.421 - 109.602 - 65
Fnet = 65.82N
Work done on the crate up the ramp, W, is given by
W = Fnet × d (distance up the plane)
W = 65.819 × 15
W = 987.285 joules
W = 987 joules (to 3 significant Figures)
(B)
to calculate the time of travel up the ramp
we use the equation of motion
where s = distance up the plane, 15m
u = Initial velocity of the crate, which is 0 for a body that is initially at rest
a = acceleration up the plane, given by
where m = mass of the crate, 20 kg
now,
from,
15 = 0 + 1.645
15 = 1.645
t = 3.01s (to 3 sig fig)
