Answer:
Explanation:
Given that,
The mass of a toy, m = 0.62 kg
Force with which a child pull the toy = 16.3 N
The force with which the toy pulled in the opposite direction = -15.8 N
We need to find the acceleration of the toy. Let F be the net force acting on the toy. It is equal to :
F = 16.3 N - (-15.8 N)
= 32.1 N
Let a be the acceleration of the toy. Using Newton' second law of motion to find it.
F = ma
So, the acceleration of the toy is 
.
Acceleration is the ratio of a change in velocity to the time over which the change happend
Answer:
a)ΔS₁ = - 9.9 J/K
ΔS₂ = 69 J/K
b)The entropy change for the rod = 0 J/K
c)ΔS = 59.1 J/K
Explanation:
Given that
T₁ = 699 K
T₂= 101 K
Q= 6970 J
Change in entropy given as
For 699 K:
ΔS₁ = - 9.9 J/K ( Negative because heat is leaving from the system)
For 101 K;
ΔS₂ = 69 J/K
The entropy change for the rod = 0 J/K
Entropy change for the system
ΔS = ΔS₂ + ΔS₁
ΔS = 69 -9.9 J/K
ΔS = 59.1 J/K
