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GenaCL600 [577]
3 years ago
5

An atomic mass unit is equal to

Physics
2 answers:
Tresset [83]3 years ago
8 0

Answer: c.  one-twelfth the mass of a carbon-12 atom.

Explanation: An atomic mass unit ( amu) is defined as \frac{1}{12} of the mass of an atom of carbon with mass number 12 , which is the most abundant isotope of carbon. Thus the carbon-12 atom has six protons and six neutrons in its nucleus.

1 amu is approximately equal to 1.67377\times 10^{-27}kg or 1.67377\times 10^{-24} g. The mass of an atom in amu is roughly equal to the sum of the number of protons and neutrons in the nucleus.

amu is used to differentiate between isotopes as they would have different mass.

elixir [45]3 years ago
6 0
One-twelfth the mass of carbon-12 atom
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Which declares two related integer vectors named personname and personage each with 50 elements?
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Both vectors should be declared to have the same number of elements.

vector<int> personName(50); vector<int> personAge(50)

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Evan drew a diagram to illustrate radiation
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The answer would be D, electromagnetic waves
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3 years ago
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A green truck is moving to the right. A red truck is moving to the left with a speed of 6 m/s. The mass of the red truck is 1,00
Contact [7]

Answer:

2 m/s

Explanation:

m_1 = Mass of red truck = 1000 kg

m_2 = Mass of green truck= 3000 kg

u_1 = Initial Velocity of red truck = 6 m/s

u_2 = Initial Velocity of green truck

v = Velocity with which they move together = 0

For elastic collision

m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow m_1u_1 + m_2u_2 =0\\\Rightarrow m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow m_1u_1 + m_2u_2 =0\\\Rightarrow u_2=-\frac{m_1u_1}{m_2}\\\Rightarrow u_2=-\frac{1000\times 6}{3000}\\\Rightarrow u_2=-2\ m/s

Velocity of the green truck is 2 m/s

8 0
3 years ago
A block of mass 22 kg is sliding along the ice at constant speed 5.0 m/s just ahead of it is q block of mass 29 kg sliding in th
mars1129 [50]

Answer:

Answer:

New speed of the 22-kg block is 1.57 m/s

Explanation:

Mass of block  

Mass of another block  

Initial speed of the block  

Initial speed  of the another block  

Initial speed  of the another block  

For conservation of momentum, we have

Substitute all the values and solving for final speed of the 22kg block is

new speed of the 22-kg block is 1.57 m/s

Couldnt write the answer so check picture

8 0
3 years ago
A sled plus passenger with total mass m = 53.1 kg is pulled a distance d = 25.3 m across a horizontal, snow-packed surface for w
Alex Ar [27]

Answer:

Explanation:

Force of friction

F = μ mg

μ is coefficient of friction , m is mass and g is acceleration due to gravity .

If f be the force applied to pull the sled , the horizontal component of force should be equal to frictional  force

The vertical component of applied force will reduce the normal force or reaction force from the ground

Reaction force R = mg - f sin28.3

frictional force = μ R where μ is coefficient of friction

frictional force = μ x (mg - f sin28.3 )

This force should be equal to horizontal component of f

μ x (mg - f sin28.3 ) = f cos 28.3

μ x mg = f μsin28.3 + f cos 28.3

f = μ x mg / (μsin28.3 + cos 28.3 )

a )

work done by pulling force  = force x displacement

f cos28.3 x d

μ x mg d cos28.3  / (μsin28.3 + cos 28.3 )

b ) Putting the given values

= .155 x 53.1 x 9.8 x 25.3 cos28.3 / ( .155 x sin28.3 + cos 28.3 )

= 1796.76 / (.073 + .88 )

= 1885.37  J

c )

Work done by frictional force

= frictional force x displacement

=  -  μ x (mg - f sin28.3 ) x d  

= -  μ x mgd + f μsin28.3  x d

= -  μ x mgd + μsin28.3  x d x μ x mg / (μsin28.3 + cos 28.3 )

d )

Putting the values in the equation above

- .155 x 53.1 x 9.8 x 25.3 +

.155 x .474 x 25.3 x .155 x 53.1 x 9.8 /( .155 x .474 + .88)

= -2040.67 + 149.92 / .95347

= -2040.67 + 157.23

= -1883.44 J .

6 0
3 years ago
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