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Annette [7]
3 years ago
9

Which parts of a compound microscope magnify objects? a convex and a concave lens two convex lenses two concave lenses one conca

ve and two convex lenses?
Physics
2 answers:
Hoochie [10]3 years ago
6 0
I believe the answer is two convex lenses. A compound microscope has two systems of lenses for greater magnification, the ocular, or eyepiece lens that one looks into and the objective lens, or the lens closest to the object. Both the ocular lens and the objective lens are convex lens.
Inessa [10]3 years ago
3 0

Answer:

two concave lenses

Explanation:

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Ishani and John now try a problem involving a charging capacitor. An uncharged capacitor with C = 6.81 μF and a resistor with R
DENIUS [597]

Answer:

Q=81.72\times10^{-6}C

I=2.1\times10^{-5}A

Explanation:

The maximum charge on the capacitor will be, at the end of the process, given by the formula (and for our values):

Q=CV=(6.81\times10^{-6}F)(12V)=81.72\times10^{-6}C

The maximum current on the resistor will be, at the beginning of the process, given by the formula (and for our values):

I=\frac{V}{R}=\frac{12V}{5.8\times10^{5}\Omega}=2.1\times10^{-5}A

5 0
3 years ago
Along some shorelines, incoming waves cause the water to simply rise and fall rather that form a surf zone. What does this tell
NARA [144]

Answer:

Explained

Explanation:

Along some shorelines, incoming waves cause the water to simply rise and fall and not form surfs because of the steepness of the shorelines. Long period waves wont form surfs at steep shores because of the breaking and unstability of waves. Wave breaks at the shallow waters. The breaking of the waves depends upon H/L ratio.

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3 years ago
Light propagate faster through medium “a” than medium “b”
dangina [55]

1) Medium "b" has more optical density

2) Light must hit the interface between the two mediums perpendicularly

Explanation:

1)

Refraction occurs when light propagates from a medium into a second medium.

The optical density of a medium is given by its index of refraction, which is defined as:

n=\frac{c}{v}

where

c is the speed of light in a vacuum

v is the speed of light in a medium

Higher index of refraction means higher optical density, and light propagater slower into a medium with higher optical density.

In this problem, light propagates faster through medium "a" than medium "b": this means that medium "a" has lower refractive index of medium "b", and so "b" has more optical density.

2)

We can answer this part by referring to Snell's law, which gives the relationship between the direction of the incident ray and of the refracted ray when light passes through the interface between two media:

n_1 sin \theta_1 = n_2 sin \theta_2

where

n_1, n_2 are the index of refraction of the two mediums

\theta_1, \theta_2 are the angle of incidence and of refraction (the angle that light makes with the normal to the surface in medium 1 and medium 2)

Here we want the direction of propagation of the light ray not to change: this means that it must be

sin \theta_1 = sin \theta_2 (1)

However, here we have two mediums "a" and "b" with different index of refraction, so

n_1\neq n_2

Therefore the only angle that can satisfy eq.(1) is

\theta_1 = \theta_2 = 0

So, the light must hit the surface perpendicular to the interface between the two mediums.

Learn more about refraction:

brainly.com/question/3183125

brainly.com/question/12370040

#LearnwithBrainly

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