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lina2011 [118]
3 years ago
15

Finally, sometimes the desired value does not directly match the units given but is derived from the calculation required. For e

xample, a sheet of metal that has a volume of 45.5 cm3 has a width of 14.8 cm and has a length 15.9 cm. What is the thickness (that is, the height) of the metal sheet in millimeters?
Chemistry
1 answer:
maria [59]3 years ago
5 0

<u>Answer:</u> The thickness of metal sheet is 1.93 mm

<u>Explanation:</u>

The metals sheet is in the form of cuboid.

To calculate the width of the metal sheet for the given volume, we use the equation to calculate the volume of cuboid, which is:

V=lbh

where,

V = volume of metal sheet = 45.5cm^3  

l = length of metal sheet = 15.9 cm

b = width of metal sheet = 14.8 cm

h = height of metal sheet = ? cm

Putting values in above equation, we get:

45.5cm^3=15.9\times 14.8\times h\\\\h=\frac{45.5}{15.9\times 14.8}=0.193cm

Converting this thickness into millimeters, we use the conversion factor:

1 cm = 10 mm

So, 0.193cm\times \frac{10mm}{1cm}=1.93mm

Hence, the thickness of metal sheet is 1.93 mm

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Answer:

The correct answer is - Frequency is the number of wavelengths, which is measured in hertz.

Explanation:

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As the frequency of a wave increases which means the number of waves increases in the unit time, the shorter the wavelength will be.

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    n = (8.2 x 10²⁴ atoms N)(1 molecule dipyrithione/ 2 atoms of N)(1 mole dipyrithione/ 6.022 x 10²³ molecules dipyrithione)

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Anit [1.1K]

The answer for the following problem is mentioned below.

  • <u><em>Therefore the final  moles of the gas is 14.2 × </em></u>10^{-4}<u><em> moles.</em></u>

Explanation:

Given:

Initial volume (V_{1}) = 230 ml

Final volume (V_{2}) = 860 ml

Initial moles (n_{1}) = 3.8 ×10^{-4} moles

To find:

Final moles (n_{2})

We know;

According to the ideal gas equation;

    P × V = n × R × T

where;

P represents the pressure of the gas

V represents the volume of the gas

n represents the no of the moles of the gas

R represents the universal gas constant

T represents the temperature of the gas

So;

    V ∝ n

\frac{V_{1} }{V_{2} } = \frac{n_{1} }{n_{2} }

where,

(V_{1}) represents the initial volume of the gas

(V_{2}) represents the final volume of the gas

(n_{1}) represents the initial  moles of the gas

(n_{2}) represents the final moles of the gas

Substituting the above values;

   \frac{230}{860} = \frac{3.8 * 10^-4}{n_{2} }

  n_{2} = 14.2 × 10^{-4} moles

<u><em>Therefore the final  moles of the gas is 14.2 × </em></u>10^{-4}<u><em> moles.</em></u>

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3 years ago
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