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2 years ago

A 2.4L balloon filled with helium at room temperature 25oC is put into liquid nitrogen

Chemistry

1 answer:

Stels [109]2 years ago

5 0

Answer:

V₂ = 0.62 L

Explanation:

Given data:

Initial volume = 2.4 L

Initial temperature = 25°C

Final temperature = -196°C

Final volume = ?

Solution:

Initial temperature = 25°C (25+273 = 298 K)

Final temperature = -196°C ( -196+273 = 77 K)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 2.4 L × 77 K / 298 k

V₂ = 184.8 L.K / 298 K

V₂ = 0.62 L

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2 years ago

Calculate the mass (g) of each product formed when 43.82 g of diborane (B₂H₆)

guajiro [1.7K]

Stoichiometry:

The area of study in chemistry concerned with the quantities of chemical species produced or required for a given chemical reaction is stoichiometry. The stoichiometric coefficients of the balanced chemical equation are often used to relate the amounts of substances to one another.

Evaluation :

The balanced chemical equation for the reaction is given as follows:

$B_{2} H_{6} + 6H_{2} O$ → $2H_{3} BO_{3} + 3H_{2}$

By using the molar mass of the given chemical species, along with the stoichiometric coefficients of the balanced chemical equation, we determine the mass of each product as:

43.82 g $B_{2} H_{6}$ × $\frac{1 Mol B_{2} H_{6} }{27.66 g}$ × $\frac{3molH_{2} }{1 molB_{2}H_{6} }$ × $\frac{2g}{1 mol H_{2} } = 9.51 g H_{2}$

43.82 g $B_{2} H_{6}$ × $\frac{1 mol B_{2} H_{6} }{27.66 g}$ × $\frac{1 mol H_{3}BO_{3} }{1 mol B_{2} H_{6} }$ × $\frac{61.8g}{1 mol H_{3} BO_{3} } = 196 gH_{3} BO_{3}$

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1 year ago

PLEASE HELP WORTH 50 POINTS NO LINKS I WILL MARK CORRECT ANSWER BRAINLIEST!!! complete this punnet square, enter your answer in

Dafna1 [17]

Answer:

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Explanation:

6 0

2 years ago

After substantial heating, 6.25 g of iron produced 18.00 g of a compound with chlorine. The empirical formula is:

babunello [35]

Answer:

Option A. FeCl3

Explanation:

The following data were obtained from the question:

Mass of iron (Fe) = 6.25g

Mass of the compound formed = 18g

From the question, we were told that the compound formed contains chlorine. Therefore the mass of chlorine is obtained as follow

Mass of chlorine (Cl) = Mass of compound formed – Mass of iron.

Mass of chlorine (Cl) = 18 – 6.25

Mass of chlorine (Cl) = 11.75g

The compound therefore contains:

Iron (Fe) = 6.25g

Chlorine (Cl) = 11.75g

The empirical formula for the compound can be obtained by doing the following:

Step 1:

Divide by their molar mass

Fe = 6.25/56 = 0.112

Cl = 11.75/35.5 = 0.331

Step 2:

Divide by the smallest

Fe = 0.112/0.112 = 1

Cl = 0.331/0.112 = 3

The empirical formula for the compound is FeCl3

3 0

2 years ago

What are some factors that might cause our percent yield to be greater than 100%? What are some factors that might cause it to b

belka [17]

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3 years ago