Answer:
oxygen = 4.7 * 10^-6
Nitrogen = = 9.7 * 10^6
Explanation:
partial pressure of oxygen = 0.20 atm
partial pressure of Nitrogen = 0.80 atm
<u>calculate the mole fractions of oxygen and Nitrogen in water </u>
Temp = 298k
applying henry's law
molar conc of oxygen in water ( Coxygen )
= Kp = 1.3 * 10^-3 Mol/L.atm * 0.20 atm = 2.6 * 10^-4 Mol
molar conc of Nitrogen in water ( Cnitrogen )
= Kp = 6.8 * 10^-4 Mol/L.atm * 0.80 atm = 5.4 * 10^-4
next Given that the number of moles in 1 liter of water = 55.5 mol
therefore the mole fraction of oxygen
= 2.6 * 10^-4 / 55.5
= 4.7 * 10^-6
mole fraction of Nitrogen
= 5.4 * 10^-4 / 55.5
= 9.7 * 10^6
1mol ------------ 3×6,02×10²³ oxygen atoms
x ------------ 2,55×10²⁴
x = 2,5×10²⁴ × 1mol / 3×6,02×10²³ ≈ 0,138*10 mol = 1,38mol
The reactions that will take place will generate Zinc salts that will
taint the food. Excessive levels of these salts can cause sickness, so
it is very important to ensure food hygiene standards are met by keeping
acidic foods away from damaging materials like zinc that will erode and
get into the food.
