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Orlov [11]
4 years ago
14

How do we think the "hot Jupiters" around other stars were formed? How do we think the "hot Jupiters" around other stars were fo

rmed? They formed as gas giants beyond the frost line and then migrated inwards. They formed as dense, rocky planets close to the star in the same orbits that they are seen today. Many planets were formed around the star but coalesced into a single planet close in. They formed as gas giants close to the star in the same orbits that they are seen today. They spun off from the young star when it was rapidly rotating.
Physics
1 answer:
FrozenT [24]4 years ago
3 0

Answer:

One of the leading theories of hot-Jupiter formation holds that gas giants in distant orbits become hot Jupiters when the gravitational influences from nearby stars or planets drive them into closer orbits. They formed as gas giants beyond the frost line and then migrated inwards.

Explanation:

In the migration hypothesis, a hot Jupiter forms beyond the frost line, from rock, ice, and gases via the core accretion method of planetary formation. The planet then migrates inwards to the star where it eventually forms a stable orbit. The planet may have migrated inward smoothly via type II orbital migration.  

Hot-Jupiters are heated gas giant planets that are very close to their stars, just a few million miles distant and orbiting their stellar hosts in just a few days. The reason why there isn't one in our Solar System is down to its formation. All gas giants form far from their star but then some migrate inwards.

Hot-Jupiters  will just happen to transit about 10% (that is, since orbital planes) this is consistent with the rate expected from geometry of . The actual frequencies of hot Jupiters around normal stars is surprisingly hard to figure out.

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Activity log - Standing Whole Body Record your time and activity below and in your unit fitness log. If a particular category do
sasho [114]

Answer:

Date: N/A

Warm-up: 5 minutes

Cool-down: 6 minutes

Type of Activity: Cardiovascular

Description of Activity and Time: Running in place for 10 minutes

Intensity Level: Moderate

Total Time: 21 minutes

Explanation: Mark me as brainiest hope this helps I just did it

6 0
4 years ago
A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is
IRINA_888 [86]

Answer:

s=4.44 m

Explanation:

Given that

Coefficient of the kinetic friction ,μ = 0.13

Initial velocity ,u= 3.4 m/s

Final velocity of the box ,v= 0 m/s

The acceleration due to friction force

a= - μ g

Now by putting the values in the above equation

a= - 0.13 x 10    ( take g= 10 m/s²)

 a= - 1.3 m/s²

We know that

v²= u ² + 2 a s

s=distance

a=acceleration

v=final speed

u=initial speed

Now by putting the values in the above equation

0²= 3.4² - 2 x 1.3 x s

s=\dfrac{3.4^2}{2\times 1.3}\ m

s=4.44 m

The distance cover by box will be 4.44 m.

6 0
3 years ago
An action force is 50 N to the left. The reaction force must be:
igomit [66]
<h2>According to Newton's Third Law:</h2><h3>"For every action,there exists an equal and opposite reaction"</h3>

<h3>So an action force of 50 N to the left, results in a 50 N reaction force to the right.</h3>

<h2>Option A</h2>
7 0
2 years ago
Read 2 more answers
You are pushing an 80.0 N wheelbarrow as shown in (Figure 1). You lift upward on the handle of the wheelbarrow so that the only
AleksandrR [38]

Answer:

Wl = 1740 N

Explanation:

maximum lift weight unaided = force exerted (F) = 650 N

length of the wheelbarrow (L) = 1.4 m

weight of the wheelbarrow (w) = 80 N

distance of center of gravity of the wheel barrow from the wheel = 0.5 m

distance of center of gravity of the load from the wheel = 0.5 m

find the weight of the load (Wl)

from the diagram attached we can see that there is going to be a rotation about the axis A. let clockwise rotation be positive

ΣT = (F x 1.4) - ((Wl x 0.5) + (w x 0.5) = 0

(F x 1.4) = ((Wl x 0.5) + (w x 0.5)

Wl =

Wl =

Wl = 1740 N

6 0
2 years ago
Io maintains a constant orbit around Jupiter because
Free_Kalibri [48]

Answer: C . The gravitational pull from Jupiter is much greater than any other forces acting on Io.

Explanation:

Let's begin by the fact Jupiter is a huge massive planet, therefore the bodies that are closest to Jupiter will have a greater gravitational force than the other bodies. That is the situation with Io, the moon closest to Jupiter.

However, Io's orbit is very elliptical and eccentric compared to the outer moons, resulting in the distortion of its shape by the gravitational force.  In fact, Io is considered the most geologically active object in the solar system, due to these variations.

4 0
4 years ago
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