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Slav-nsk [51]
1 year ago
5

An action force is 50 N to the left. The reaction force must be:

Physics
2 answers:
igomit [66]1 year ago
7 0
<h2>According to Newton's Third Law:</h2><h3>"For every action,there exists an equal and opposite reaction"</h3>

<h3>So an action force of 50 N to the left, results in a 50 N reaction force to the right.</h3>

<h2>Option A</h2>
saveliy_v [14]1 year ago
7 0
Answer is B
50 N down
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How many Sig Figs (Significant Figures) are in each number?<br><br> 5070.0<br><br> 870.064080
nlexa [21]

∑ Hey, Lethality ⊃

Answer:

5070.0 has 5 significant figures

870.064080 has 9 significant figures

Explanation:

<u><em>Given:</em></u>

<em>How many Sig Figs (Significant Figures) are in each number?</em>

<em>5070.0</em>

<em>870.064080</em>

<u><em>Solution:</em></u>

<em>-------------------------------------------------------------------------------------------------------------</em>

<em>5070.0</em>

<em>5070.0 has 5 significant figures ( 5 , 0 , 7 , 0 , and 0 )</em>

<em>Number of significant figures: 5</em>

<em>-------------------------------------------------------------------------------------------------------------</em>

<em>870.064080</em>

<em>870.064080 has 9 significant figures ( 8, 7 ,0,0, 6,4,0,8 and 0 )</em>

<em>Number of significant figures: 9</em>

<em>-------------------------------------------------------------------------------------------------------------</em>

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<em>8/23/2022</em>

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Katherine johnson’s skill in what field led to nasa’s first moon voyage?
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Temperature which is solid becomes a liquid
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Answer:

The answer would be melting point.

Explanation:

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Why is a shadow formed
a_sh-v [17]

Answer:

Shadows are made by blocking light. Light rays travel from a source in straight lines. If an opaque (solid) object gets in the way, it stops light rays from traveling through it. The size and shape of a shadow depend on the position and size of the light source compared to the object.

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A point charge with a charge q1 = 4.00 μC is held stationary at the origin. A second point charge with a charge q2 = -4.10 μC mo
GrogVix [38]

Answer:

W = -0.480 J

Explanation:

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b = \sqrt{(0.27-0)^2+(0.27-0)^2}

b = 0.381

k = 8.99 × 10⁹ Nm²/C²

W = 8.99\times 10^9\times 4\times 10^{-6}\times (-4.1 \times 10^{-6})(\dfrac{1}{0.17}+\dfrac{1}{0.381})

W = [-147.436\times (5.88-2.62)\times 10^{-3}]J

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