Answer:
Explanation:
given
m= 17.5kg
F= 75N
d= 5.7m
∪=0.150
θ= 21°
a. W = Fcos θ × d
75cos21° ×5.7
=399.106J
b. normal force is zero. 0 Joules
cos 90°=0
Answer:
θr = 55.2 °
Explanation:
The law of reflection states that the angle of incidence and the angles of reflection is the same.
Let's use trigonometry to find the angle between the reflected ray, where the horizontal distance x = 55.9 cm and the vertical distance is y = 38.9 cm
tan θ = y / x
tan θ = 38.9 / 55.9
θ = tan⁻¹ (0.6959)
θ = 34.8°
This angle is measured with respect to the x-axis (horizontal), but in general the angles in optics are measured from the y-axis so that the angle is
θ = 90 - 34.8
θr = 55.2 °
Answer: 170km/hr to the South
Explanation:
The resultant velocity of the plane ilwill be gotten by adding the value of the velocities of the plane with the tallwind. It should be noted that the direction of the wind is.takwn into consideration.
Therefore, the resultant velocity of the plane will be:
= 20km/hr + 150km/hr
= 170km/hr to the South
Answer:
c. The truck with greater speed
Explanation:
Energy can be defined as the ability (capacity) to do work. The two (2) main types of energy are;
a. Gravitational potential energy (GPE): it is an energy possessed by an object or body due to its position above the earth.
b. Kinetic energy (KE): it is an energy possessed by an object or body due to its motion.
Mathematically, kinetic energy is given by the formula;

Where;
K.E represents kinetic energy measured in Joules.
M represents mass measured in kilograms.
V represents speed or velocity measured in metres per seconds square.
From the above formula, we can deduce that the kinetic energy of an object is directly proportional to the square of the value of its velocity or speed.
Hence, the truck with greater speed would have a greater amount of kinetic energy.
Answer:
The classification of that same issue in question is characterized below.
Explanation:
The given values are:
Current, I = 50.0 A
Diameter, d = 0.10 cm
(a)...
As we know,
⇒ Magnetic force = Copper wire's weight
So,
⇒ 
On putting the estimated values, we get
⇒ 
⇒ 
⇒ 
(b)...
As we know,
⇒ 
⇒ 
⇒ 
⇒