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Artemon [7]
3 years ago
9

I need to know everything about mars. I need to do a full 3 page essay. please help!

Physics
1 answer:
zheka24 [161]3 years ago
4 0

Answer:

Mars was the Roman god of War along with an agricultural guardian. He is most closely related to the god Ares of Greek Mythology. In Roman mythology, he was second in importance to Jupiter, Rome's god of the Skies and Weather. Jupiter was the king of the Roman Pantheon, husband of the queen of gods Juno. He was also Mars' father. Unlike his Greek Counterpart, Ares who was most known for his hot headed temper and associated with hate and anger, Mars was part of the Romans <em>Archaic Triad</em>, sort of like the Big Three of Greek religion. The members of said Triad included Mars, Jupiter, and Quirinus, who had no Greek equivalent. Mars was most commonly depicted in posed of valor and strength, carrying swords or shields. He wore common Roman armor, including the plumed helmet. He was pictured as a strong leader of the Roman Army. The fourth planet from the Sun was given the name Mars when it was first discovered because it was red, much like the main color the Roman god was affiliated with.

This was mostly just random facts but i hope it helped some with your essay :)

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If two objects of the same size move through the air at different speeds, which encounters the greater air resistance?a. The fas
blagie [28]

Answer:

Option A is correct.

(The faster object encounters more resistance)

Explanation:

Option A is correct. (The faster object encounters more resistance)

Air resistance depends on various factors:

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  • Cross-sectional area of the object
  • Shape of the object

Formula:

F=\frac{1}{2}C_d\rho A v^{2}

As the speed of the object increases the amount of Air resistance/drag increases on the object, as the above formula shows direct relation between Air resistance/drag and velocity i.e F ∝ v^2.

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3 years ago
3.9 divided by 15 gcuu
Vsevolod [243]

0.26 there you go buddy

8 0
3 years ago
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Write a hypothesis about the use of an object’s physical characteristics to determine its density. Use the format "if . . . then
mash [69]
For this case you must first know the definition of density.
 D = m / v
 where,
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 v: volume.
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A 2.61 g lead weight, initially at 11.1 ∘C, is submerged in 7.67 g of water at 52.6 ∘C in an insulated container. What is the fi
sleet_krkn [62]

Answer:

Equilibrium temperature will be T=52.2684^{\circ}C

Explanation:

We have given weight of the lead m = 2.61 gram

Let the final temperature is T

Specific heat of the lead c = 0.128

Initial temperature of the lead = 11°C

So heat gain by the lead = 2.61×0.128×(T-11°C)

Mass of the water m = 7.67 gram

Specific heat = 4.184

Temperature of the water = 52.6°C

So heat lost by water = 7.67×4.184×(T-52.6)

We know that heat lost = heat gained

So 2.61\times 0.128\times (T-11)=7.67\times 4.184\times (52.6-T)

0.334T-3.67=1688-32.031T

T=52.2684^{\circ}C

5 0
3 years ago
As you finish listening to your favorite compact disc (CD), the CD in the player slows down to a stop. Assume that the CD spins
Colt1911 [192]

Answer:

A. w=8.3rev/s

a_v=3.21rev/s^2

B. rev=10.79rev

Explanation:

A.

500rpm

500rpm*\frac{1minute}{60seg}=8.33\frac{rev}{s}

the time is about 2.60s knowing the acceleration is:

a_v=\frac{w}{t}

so:

w=8.3rev/s

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B.

The CD stop so the final velocity is vf=0 so:

Total revolutions:

8.3rev/s*2.60s=21.58rev

21.58rev/2=10.79 rev

3 0
3 years ago
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