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ludmilkaskok [199]
4 years ago
8

Activity log - Standing Whole Body Record your time and activity below and in your unit fitness log. If a particular category do

es not apply, leave it blank. Date: Warm-up: Cool-down: Type of Activity: (Cardiovascular, Muscular, or Flexibility) Description of Activity and Time: Intensity Level: (Moderate or Vigorous) Total Time:
Physics
1 answer:
sasho [114]4 years ago
6 0

Answer:

Date: N/A

Warm-up: 5 minutes

Cool-down: 6 minutes

Type of Activity: Cardiovascular

Description of Activity and Time: Running in place for 10 minutes

Intensity Level: Moderate

Total Time: 21 minutes

Explanation: Mark me as brainiest hope this helps I just did it

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Why is the likelihood of amajor earthquake along the san andreas fault so worrisome??
Softa [21]
Because a lot of people live along the fault line and there would be lots of death and much property damage.
5 0
3 years ago
You look at a barometer and see that the air pressure is getting much higher... How will the weather probably change? *
Murljashka [212]

Answer:

The weather will clear up and get sunnier.

Explanation:As weather forecasters monitor air pressure, falling barometer measurements can signal that bad weather is on the way. In general, if a low pressure system is on its way, be prepared for warmer weather with storms and rain. If a high pressure system is coming, you can expect clear skies and cooler temperatures.

hope this helped:)

Brainliest?

8 0
3 years ago
Read 2 more answers
What information did the movement of the bubble over a specified distance in the calibrated respirometer provide
emmasim [6.3K]

Answer:

The following explanatory section gives an explanation of this question.

Explanation:

  • This means that perhaps the bubble moves more than a certain duration throughout the calibration breath meter offers the rate as well as oxygenation consumed inside this cell.
  • Inside that respirometer, oscillation of something like the bubble gave a technique of multiplying the quantity of oxygenation that is used by the seedlings mostly through cell membrane breathing.
3 0
3 years ago
The work done by an external force to move a -6.70 μc charge from point a to point b is 1.20×10−3 j .
ASHA 777 [7]

Answer:

108.7 V

Explanation:

Two forces are acting on the particle:

- The external force, whose work is W=1.20 \cdot 10^{-3}J

- The force of the electric field, whose work is equal to the change in electric potential energy of the charge: W_e=q\Delta V

where

q is the charge

\Delta V is the potential difference

The variation of kinetic energy of the charge is equal to the sum of the work done by the two forces:

K_f - K_i = W + W_e = W+q\Delta V

and since the charge starts from rest, K_i = 0, so the formula becomes

K_f = W+q\Delta V

In this problem, we have

W=1.20 \cdot 10^{-3}J is the work done by the external force

q=-6.70 \mu C=-6.7\cdot 10^{-6}C is the charge

K_f = 4.72\cdot 10^{-4}J is the final kinetic energy

Solving the formula for \Delta V, we find

\Delta V=\frac{K_f-W}{q}=\frac{4.72\cdot 10^{-4}J-1.2\cdot 10^{-3} J}{-6.7\cdot 10^{-6}C}=108.7 V

4 0
3 years ago
Read 2 more answers
What's the mass show the work?
Alja [10]
You do this one just like the other one that I just solved for you.

For this one ...

The density of the object is 2.5 gm/cm³.
We know that every cm³ of it we have contains 2.5 gm of mass.
We have to find out how many cm³ we have.

The question tells us:  We have  2.0 cm³.

Each cm³ of space that the object occupies contains 2.5 gm of mass.

So the 2.0 cm³ that we have contains (2 x 2.5 gm) = 5 gms.
That's the mass of our object.
6 0
4 years ago
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