Answer:
22N West
Explanation:
45-23 because they are in opposite directions.
Answer:
35.6 N
Explanation:
We can consider only the forces acting along the horizontal direction to solve the problem.
There are two forces acting along the horizontal direction:
- The horizontal component of the pushing force, which is given by
![F_x = F cos \theta](https://tex.z-dn.net/?f=F_x%20%3D%20F%20cos%20%5Ctheta)
with ![\theta=41.9^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D41.9%5E%7B%5Ccirc%7D)
- The frictional force, whose magnitude is
![F_f = \mu mg](https://tex.z-dn.net/?f=F_f%20%3D%20%5Cmu%20mg)
where
, m=8.2 kg and g=9.8 m/s^2.
The two forces have opposite directions (because the frictional force is always opposite to the motion), and their resultant must be zero, because the suitcase is moving with constant velocity (which means acceleration equals zero, so according to Newton's second law: F=ma, the net force is zero). So we can write:
![F_x - F_f=0\\F_x = F_f\\F cos \theta = \mu mg\\F=\frac{\mu mg}{cos \theta}=\frac{(0.33)(8.2 kg)(9.8 m/s^2)}{cos(41.9^{\circ})}=35.6 N](https://tex.z-dn.net/?f=F_x%20-%20F_f%3D0%5C%5CF_x%20%3D%20F_f%5C%5CF%20cos%20%5Ctheta%20%3D%20%5Cmu%20mg%5C%5CF%3D%5Cfrac%7B%5Cmu%20mg%7D%7Bcos%20%5Ctheta%7D%3D%5Cfrac%7B%280.33%29%288.2%20kg%29%289.8%20m%2Fs%5E2%29%7D%7Bcos%2841.9%5E%7B%5Ccirc%7D%29%7D%3D35.6%20N)
The combined momentum is 4000 kg m/s south
Explanation:
The total combined momentum of the two cars is given by the vector addition of the momenta of the two cars.
For this problem, we choose north as positive direction and south as negative direction.
The momentum of the first car travelling north is given by:
![p_1 = m_1 v_1](https://tex.z-dn.net/?f=p_1%20%3D%20m_1%20v_1)
where
is the mass of the car
is its velocity
Substituting,
![p_1 = (1600)(8)=+12800 kg m/s](https://tex.z-dn.net/?f=p_1%20%3D%20%281600%29%288%29%3D%2B12800%20kg%20m%2Fs)
The momentum of the second car travelling south is given by:
![p_2 = m_2 v_2](https://tex.z-dn.net/?f=p_2%20%3D%20m_2%20v_2)
where
is the mass of the car
is its velocity (negative because the car travels south)
Substituting,
![p_2 = (1400)(-12)=-16800 kg m/s](https://tex.z-dn.net/?f=p_2%20%3D%20%281400%29%28-12%29%3D-16800%20kg%20m%2Fs)
And therefore, the combined momentum is
![p=p_1 + p_2 = +12800 + (-16800)=-4000 kg m/s](https://tex.z-dn.net/?f=p%3Dp_1%20%2B%20p_2%20%3D%20%2B12800%20%2B%20%28-16800%29%3D-4000%20kg%20m%2Fs)
where the negative sign means the direction of the total momentum is south.
Learn more about momentum:
brainly.com/question/7973509
brainly.com/question/6573742
brainly.com/question/2370982
brainly.com/question/9484203
#LearnwithBrainly
Forces are exerted I believe : all of the above
The action force might be Tyler throwing the ball
I don't know the last one