Question

You are pushing an 80.0 N wheelbarrow as shown in (Figure 1). You lift upward on the handle of the wheelbarrow so that the only point of contact between the wheelbarrow and the ground is at the front wheel. Assume the distances are as shown in the figure, where 0.50 m is the horizontal distance from the center of the wheel to the center of gravity of the wheelbarrow. The center of gravity of the dirt in the wheelbarrow is assumed to also be a horizontal distance of 0.50 m from the center of the wheel. Suppose that the maximum total upward force that you can apply to the wheelbarrow handles is 75 lb.

Answer 1

Answer:

Wl = 1740 N

Explanation:

maximum lift weight unaided = force exerted (F) = 650 N

length of the wheelbarrow (L) = 1.4 m

weight of the wheelbarrow (w) = 80 N

distance of center of gravity of the wheel barrow from the wheel = 0.5 m

distance of center of gravity of the load from the wheel = 0.5 m

find the weight of the load (Wl)

from the diagram attached we can see that there is going to be a rotation about the axis A. let clockwise rotation be positive

ΣT = (F x 1.4) - ((Wl x 0.5) + (w x 0.5) = 0

(F x 1.4) = ((Wl x 0.5) + (w x 0.5)

Wl =

Wl =

Wl = 1740 N