You are pushing an 80.0 N wheelbarrow as shown in (Figure 1). You lift upward on the handle of the wheelbarrow so that the only
point of contact between the wheelbarrow and the ground is at the front wheel. Assume the distances are as shown in the figure, where 0.50 m is the horizontal distance from the center of the wheel to the center of gravity of the wheelbarrow. The center of gravity of the dirt in the wheelbarrow is assumed to also be a horizontal distance of 0.50 m from the center of the wheel. Suppose that the maximum total upward force that you can apply to the wheelbarrow handles is 75 lb.
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Answer:
The anserrs to the question are
(a) The temperature would be 566.67 K and
(b) The pressure of the resulting air stream is 14 bar
Explanation:
Here the two streams of gases meet ad form a single stream
The steady-flow energy equation can be implemented at the mixing point of the to streams as follows
mₐhₐ₁ + mₙ hₙ₁ + Q° + W° = mₐhₐ₂ + mₙhₙ₂
Where the flow is adiabatic, we have
Q = 0 and W = 0 hence
mₐhₐ₁ + mₙ hₙ₁ = mₐhₐ₂ + mₙhₙ₂ where h = cp×T we have
mₐcpₐ×Tₐ + mₙcpₙ×Tₙ = mₐcpₐ×T + mₐcpₙ×T
Therefore the final temperature T is given by
for the same kind of gas cpₐ =cpₙ therefore
where mₐ and mₙ are mass flow rate
Therefore we have where Tₐ = = 900 K and Tₙ = 400 K and mₙ = 2mₐ gives
=
= 1700/3 = 566.67 K
From Dalton's law, the total pressure of a mixture of gases is equal to the sum of the partial pressures of the components of the mixture
Therefore the total pressure of the combined stream = pₐ + pₙ = p
= 12 bar + 2 bar = 14 bar
Stream pressure = 14 bar