A.<span>.Glucose and carbon dioxide</span>
if all sides are unequal it is scalene and if one angle adds up to 90 while the rest are different youve proven it.
Given the pH of the solution, we can determine [H⁺].
pH = -log[H⁺]
[H⁺] = 10⁻⁷·⁷⁸
[H⁺] = 1.659586907 x 10⁻⁸ M
We also know that pOH = 14 - pH. Thus, the pOH is 6.22. Given the pOH of the solution, we can determine [OH⁻].
pOH = -log[OH⁻]
[OH⁻] = 10⁻6.22
[OH⁻] = 6.02559586 x 10⁻⁷ M
The ionic product of water Kw, can then be calculated using the following equation.
Kw = [H⁺][OH⁻]
Kw = (1.659586907 x 10⁻⁸)(6.02559586 x 10⁻⁷)
Kw = 1.0 x 10⁻¹⁴
