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3 years ago

Suppose a truck has a momentum of 40,120 kg • meters per second and a mass of 1,180 kg. What is the truck’s velocity?

Physics

1 answer:

Sedaia [141]3 years ago

7 0

34 meters per second because 1180 kg times 34 Mps is 40120 kg/mps

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Be sure to answer all parts. Assume the diameter of a neutral helium atom is 1.40 × 102 pm. Suppose that we could line up helium

ss7ja [257]

Answer:

The number of atoms are $1.86\times10^{8}$ .

Explanation:

Given that,

Diameter $D = 1.40\times10^{2}\ pm$

$D=1.40\times10^{2}\times10^{-12}\ m$

Distance = 2.60 cm

We calculate the number of atoms

Using formula of numbers of atoms

$Number\ of\ atoms =\dfrac{2.60\times10^{-2}}{1.40\times10^{2}\times10^{-12}}$

$Number\of\atoms =1.86\times10^{8}$

Hence, The number of atoms are $1.86\times10^{8}$ .

8 0

3 years ago

Which statement is true regarding flexibility? A. joint's range of motion cannot be maintained with age. b.A joint's range of mo

Alex777 [14]

<span>the statement that is true regarding flexibility is : b. a joint's range of motion will be lost if the joint is not used regularly. Our body is like a machine. If we not constantly heat it up, our body will be more prone to injury. We can see that the old people who lived within the tribe in the middle of the mountain are far stronger than the one who lived in the city.</span>

3 0

3 years ago

Read 2 more answers

Dolphins and other sea creatures can leap to great heights by swimming straight up and exiting the water at a high speed. A 200

scoundrel [369]

Answer:

i don't know sorry

Explanation:

so if a pie is baked

5 0

3 years ago

A force F = (cx - 3.00x^2)i^ acts on a virus as the virus moves along an x axis, with F measured in Newtons, x in meters, and c

Ket [755]

Answer:

c = 4

Explanation:

From work-energy theorem KE = workdone.

Given F = (cx - 3.00x²)i

W = ∫Fdx = ∫(cx - 3.00x²)dx = cx²/2 –3.00x³/3 + A

W = cx²/2 –x³ + A

Where A is a constant

At x = 0, KE = 20J

So W = 20J at x = 0

20 = c×0 - 0 +A

A = 20

So W = cx²/2 –x³ + 20

Also when x = 3.00m, W = KE = 11J

11 = c×3²/2 – 3³ + 20

11 = 4.5c – 7

4.5c = 11 + 7

4.5c = 18

c = 18/4.5 = 4

c = 4

6 0

4 years ago

Consider a collection of charges in a given region and suppose all other charges are distant and have a negligible effect. Furth

AlladinOne [14]

Answer:

E. Some charges in the region are positive, and some are negative.

Explanation:

Electric potential is given as;

$V = \frac{W}{Q}$

where;

W is the work done in moving a charge between two points which have a difference in potential

Q is quantity of charge in the given region

If the electric potential at a given point in the region is zero, then sum of the charges in the given region must be equal to zero. For the charges to sum to zero, some will be positive while some will be negative,.

Therefore, the correct statement in the given options is "E"

E. Some charges in the region are positive, and some are negative.

3 0

3 years ago