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Svetradugi [14.3K]
3 years ago
14

The force that probably propels the movement of the earth s gigantic rock plates is

Physics
1 answer:
il63 [147K]3 years ago
4 0

The correct answer is:

c. convection.

The heating of magma and the continuous cycle of evolution of the magma creating a convection current is the reason for the evolution of Earths tectonic plates.

Explanation:

Tectonic plates are ready to move because the Earth's lithosphere has higher strength than the underlying asthenosphere. Lateral density changes in the mantle appear in convection. Plate movement is believed to be driven by a succession of the motion of the seafloor apart from the extended ridge (due to variations in topography and density of the crust.

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What does the symbol "E3" represent? ...?
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The symbol "E3" represents the energy of electrons in the third energy level.


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7 0
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The electronegativity of nonmetals is relatively __________ as compared to the electronegativity of metals.
solniwko [45]
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Electronegativity generally increases from the left of the P.T.(metals) to the right (nonmetals).
7 0
3 years ago
What is the mass of a baseball that has a kinetic energy of 105 J and is traveling at 10 m/s?​
kkurt [141]

Answer:

\boxed {\boxed {\sf 2.1 \ kilograms}}

Explanation:

Kinetic energy is the energy an object possesses due to motion. The formula 1/2 the product of mass and the squared velocity.

E_k=\frac{1}{2} mv^2

We know the baseball's kinetic energy is 105 Joules. It is also traveling at a velocity of 10 meters per second. `

First, convert the units of Joules to make unit cancellation easier later in the problem. 1 Joule (J) is equal to 1 kilogram square meter per square second (kg*m²/s²). The baseball's kinetic energy of 105 J is equal to 105 kg*m²/s².

Now we know 2 values:

  • E_k= 105 \ kg*m^2/s^2
  • v= 10 \ m/s

Substitute these values into the formula.

105 \ kg*m^2/s^2= \frac{1}{2} m (10 \ m/s)^2

Now we need to solve for m, the mass. Solve the exponent.

  • (10 m/s)²= 10 m/s * 10 m/s = 100 m²/s²

105 \ kg *m^2/s^2 = \frac{1}{2} m (100 \ m^2/s^2)

Multiply on the right side.

105 \ kg *m^2/s^2 =  m (\frac{1}{2} * 100 \ m^2/s^2)

105 \ kg *m^2/s^2 =  m (50 \ m^2/s^2)

The variable, m, is being multiplied by 50 square meters per square second. The opposite of multiplication is division, so we divide both sides by that value.

\frac {105 \ kg *m^2/s^2 }{50 \ m^2/s^2}=  \frac{ m (50 \ m^2/s^2)}{50 \ m^2/s^2}

\frac {105 \ kg *m^2/s^2 }{50 \ m^2/s^2}= m

The units of square meter per square second will cancel out.

\frac {105 }{50} \ kg= m

2.1 \ kg=m

The mass of the baseball is <u>2.1 kilograms. </u>

5 0
3 years ago
Determine the value of n so that the vectors A and B are perpendicular: Ā = î + 5j + nk and B = 2î - j + k
Tanya [424]

If \vec A and \vec B are perpendicular, then their dot product is zero. This means

\vec A \cdot \vec B = (\vec\imath + 5\,\vec\jmath + n\,\vec k) \cdot (2\,\vec\imath - \vec\jmath + \vec k) = 2 - 5 + n = 0

Solving for n is trivial; it follows that n = 3.

6 0
2 years ago
A 1 200-kg car traveling initially at vCi 5 25.0 m/s in an easterly direction crashes into the back of a 9 000-kg truck moving i
sukhopar [10]

Answer:

The velocity of the truck after the collision is 20.93 m/s

Explanation:

It is given that,

Mass of car, m₁ = 1200 kg

Initial velocity of the car, v_{Ci}=25\ m/s

Mass of truck, m₂ = 9000 kg

Initial velocity of the truck, v_{Ti}=20\ m/s

After the collision, velocity of the car, v_{Cf}=18\ m/s

Let v is the velocity of the truck immediately after the collision. The momentum of the system remains conversed.

initial\ momentum=final\ momentum

1200\ kg\times 25\ m/s+9000\ kg\times 20\ m/s=1200\ kg\times 18+9000\ kg\times v

210000-21600=9000\ kg\times v

v=20.93\ m/s

So, the velocity of the truck after the collision is 20.93 m/s. Hence, this is the required solution.

8 0
3 years ago
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