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3 years ago

Which of the following is an electric potential?

Physics

2 answers:

Dennis_Churaev [7]3 years ago

8 0

Answer:

D. 2.5 V

Explanation:

Electric potential of a point in space is a scalar magnitude that allows a measurement of the electric field at that point to be obtained through the electrostatic potential energy that a electric charge would acquire if it is placed at that point.

OLEGan [10]3 years ago

6 0

Answer:

2.5V

Explanation:

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How does gravity influence our annual calendar?

stellarik [79]

makes it so it doesnt float off the hook lol idk

4 0

4 years ago

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Find p(t, the x component of the total momentum of the system at time t. express your answer in terms of m1, m2, v1(t, and v2(t.

denpristay [2]

The X-component of the momentum of the system is $\boxed{{p_x}={m_1}{v_1}\left(t\right)+{m_2}{v_2}\left(t\right)}$ .

Further Explanation:

The momentum of a body is the amount of motion contained by the body. The momentum of a body is expressed as the product of the mass and velocity of the body at the particular instant.

The momentum of the body is represented as:

$\boxed{p=m\times v}$

For a system of particles, the momentum of the whole system is the vector sum of individual momentum of all the particles.

${\vec p_{net}}={\vec p_1}+{\vec p_2}+{\vec p_3}.....$

Here, ${\vec p_{net}}$ is the net momentum of the system.

In the given question, both the particles are moving in the same direction i.e. X-direction. Therefore, the net momentum of the system in X-direction is the sum of the two momentum.

The velocity of the first particle at time $t$ is ${v_1}\left(t\right)$ .

The momentum of the first particle is:

${p_1}={m_1}{v_1}\left(t\right)$

The velocity of the second particle at time $t$ is ${v_2}\left(t\right)$ .

The momentum of the second particle is:

${p_2}={m_2}{v_2}\left(t\right)$

The X-component of the net momentum of the system is:

$\begin{aligned}{p_x}&={p_1}+{p_2}\\&={m_1}{v_1}\left(t\right)+{m_2}{v_2}\left(t\right)\\\end{aligned}$

Thus, the X-component of the momentum of the system is $\boxed{{p_x}={m_1}{v_1}\left(t\right)+{m_2}{v_2}\left(t\right)}$ .

Learn More:

1. You are riding on a roller coaster that starts from rest at a height of 25.0 m and moves down a frictionless track brainly.com/question/10177389

2. A 700-kg car, driving at 29 m/s, hits a brick wall and rebounds with a speed of 4.5 m/s brainly.com/question/9484203

3. A 50-kg meteorite moving at 1000 m/s strikes earth. Assume the velocity is along the line joining earth's center brainly.com/question/6536722

Answer Details:

Grade: High School

Subject: Physics

Chapter: Force and Momentum

Keywords:

Momentum, X-component, total momentum, isolated system, velocity of the particle, v1(t), v2(t), composed of two blocks, masses m1 and m2.

6 0

3 years ago

A diver of mass 101 kg jumps upward off a diving board and into the water. The diving board is 6 m above the water.

goblinko [34]

PART a)

As we know that kinetic energy is given by

$K = \frac{1}{2} mv^2$

here we know that

m = 101 kg

v = 1.2 m/s

now from above equation

$K = \frac{1}{2}(101)(1.2)^2$

$K = 72.72 J$

Part B)

As we know that gravitational potential energy is given by

$U = mgh$

Now we know that here there is no loss in energy due to friction

So she will gain its potential energy by the loss of kinetic energy

So her gain in potential energy at the top = initial kinetic energy

So gain in potential energy = 72.72 J

PART C)

So here we can use the formula of potential energy in order to find the maximum height

$U = mgh$

$72.72 = 101(9.81)h$

$h = 0.0735 m$

so she will be 7.35 cm above the initial height

PART D)

By energy conservation we can find the final speed when she hit the water

So by energy conservation law we know that

$KE_i + U_i = KE_f$

$72.72 + 101(9.8)6 = \frac{1}{2}(101)v_f^2$

now we have

$v_f^2 = 119.04$

$v_f = 10.91 m/s^2$

3 0

3 years ago

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A gold bar has a volume of 4.7cm cubed and a density of 19.3 g/cm cubed. What is it’s mass?

joja [24]

Explanation:

Mass = density × volume

m = 19.3 g/cm³ × 4.7 cm³

m = 90.7 g

Round as needed.

7 0

3 years ago

If a diver-in-training is put into a pressurized suit, by how much would the pressure have to be raised (in atmospheres) above a

Sever21 [200]

This is an incomplete question, here is a complete question.

The bulk modulus for bone is 15.0 (GPa). If a diver-in-training is put into a pressurized suit, by how much would the pressure have to be raised (in atmospheres) above atmospheric pressure to compress her bones by 0.130% of their original volume?

Answer : The change in pressure will be, $1.95\times 10^7Pa$