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Evgen [1.6K]
3 years ago
6

A 15 kg kangaroo jumps with an upward acceleration of 3 m/s2 by pushing hard off the ground.

Physics
2 answers:
Ilya [14]3 years ago
6 0

Explanation:

The net force would be upwards since the kangaroo would have to overcome gravity to jump

patriot [66]3 years ago
3 0

Explanation:

The net force would be upwards since the kangaroo would have to overcome gravity to jump

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Two men pull on a 31-kg box with forces 8.3 N and 6.6 N in opposite directions.
kykrilka [37]

The resultant acceleration of the box is 0.055 m/s² in the direction of the greater force.

The given parameters:

  • Mass of the box, m = 31 kg
  • Two applied forces, = 8.3 N and 6.6 N

<h3>Resultant force on the box</h3>

The resultant force on the box is calculated as follows;

F_{net} = F_1 - F_2\\\\F_{net} = 8.3 \ N - \ 6.6 \ N\\\\F_{net} = 1.7 \ N

<h3>Resultant acceleration of the box</h3>

The resultant acceleration of the box is calculated as follows;

F = ma\\\\a = \frac{F}{m} \\\\a = \frac{1.7}{31} \\\\a = 0.055  \ m/s^2

Thus, the resultant acceleration of the box is 0.055 m/s² in the direction of the greater force.

Learn more about resultant acceleration here: brainly.com/question/26216029

4 0
2 years ago
If I want to calculate the normal force of an object on two legs but the weight of the object is not uniform throughout, how do
RoseWind [281]

Use the right equation. To calculate the normal force of an object at an angle, you need to use the formula: N = m * g * cos (x) For this equation, N refers to the normal force, m refers to the object's mass, g refers to the acceleration of gravity, and x refers to the angle of incline.

6 0
2 years ago
PLEASE HELP! ASAP!
Mice21 [21]

Answer:

1.) Radio

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Explanation:

5 0
3 years ago
action and reaction are equal in magnitude and opposite direction then why they don't balance each other
Harrizon [31]
Action and reaction are equal in magnitude and opposite direction by they don't balance each other because they don't occur on the same body. Action is involved on one body and reaction is involved on another body.
Hope you understood...
8 0
3 years ago
If you are in an elevator that speed up then the apparent weight is
Sholpan [36]

Answer:

Fnet - Fg

Explanation:

When an object is in an elevator, its weight varies with respect to the direction of movement of the elevator and the elevators acceleration.

The weight, W, of an object can be expressed as;

W = mg

where m is the object's mass, and g is the acceleration due gravity.

If the object is in an elevator that speed up, an apparent weight would be felt since both mass and elevator are moving against gravitational pull of the earth.

So that,

W_{net} = mg + ma

where: mg is the weight of the object, and ma is the apparent weight.

Apparent weight (ma) = W_{net} - mg

3 0
3 years ago
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