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Evgen [1.6K]
3 years ago
6

A 15 kg kangaroo jumps with an upward acceleration of 3 m/s2 by pushing hard off the ground.

Physics
2 answers:
Ilya [14]3 years ago
6 0

Explanation:

The net force would be upwards since the kangaroo would have to overcome gravity to jump

patriot [66]3 years ago
3 0

Explanation:

The net force would be upwards since the kangaroo would have to overcome gravity to jump

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Farmer Brown has sprayed his fields to kill the grasshoppers eating the grass in his pastures. Predict what will happen to the o
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Its a major factor in the food chain the grass hopers could be gone and some other animals and insects would die from starving and it would mess up the entire food chain for that area hope this helps had the same free response for k12 plz give me brainliest thx
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3 years ago
What is the biggest barrier to the use of renewable energy in the United States?
storchak [24]
The biggest barrier to the use of renewable energy in the United States is the  Citizen opposition to negative environmental impact.
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7 0
2 years ago
what is the potential energy of the ball when it gets to its maximum height just before falling back to the ground​
love history [14]

Answer:

I will say that the the potential energy will be at its maximum.

Explanation:

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6 0
2 years ago
A vector → A has a magnitude of 56.0 m and points in a direction 30.0° below the negative x axis. A second vector, → B , has a m
MissTica

Answer:

  • The magnitude of the vector \vec{C} is 107.76 m

Explanation:

To find the components of the vectors we can use:

\vec{A} = | \vec{A} | \ ( \ cos(\theta) \ , \ sin (\theta) \ )

where | \vec{A} | is the magnitude of the vector, and θ is the angle over the positive x axis.

The negative x axis is displaced 180 ° over the positive x axis, so, we can take:

\vec{A} = 56.0 \ m \ ( \ cos( 180 \° + 30 \°) \ , \ sin (180 \° + 30 \°) \ )

\vec{A} = 56.0 \ m \ ( \ cos( 210 \°) \ , \ sin (210 \°) \ )

\vec{A} = ( \ -48.497 \ m \ , \ - 28 \ m \ )

\vec{B} = 82.0 \ m \ ( \ cos( 180 \° - 49 \°) \ , \ sin (180 \° - 49 \°) \ )

\vec{B} = 82.0 \ m \ ( \ cos( 131 \°) \ , \ sin (131 \°) \ )

\vec{B} = ( \ -53.797 \ m \ , \ 61.886\ m \ )

Now, we can perform vector addition. Taking two vectors, the vector addition is performed:

(a_x,a_y) + (b_x,b_y) = (a_x+b_x,a_y+b_y)

So, for our vectors:

\vec{C} = ( \ -48.497 \ m \ , \ - 28 \ m \ ) + ( \ -53.797 \ m \ ,  ) = ( \ -48.497 \ m \ -53.797 \ m , \ - 28 \ m \ + \ 61.886\ m \ )

\vec{C} = ( \ - 102.294 \ m , \ 33.886 m \ )

To find the magnitude of this vector, we can use the Pythagorean Theorem

|\vec{C}| = \sqrt{C_x^2 + C_y^2}

|\vec{C}| = \sqrt{(- 102.294 \ m)^2 + (\ 33.886 m \)^2}

|\vec{C}| =107.76 m

And this is the magnitude we are looking for.

5 0
3 years ago
How long was a 60 W light bulb turned on if it used a total of 580 J of energy?
icang [17]
Here's the tool you need.  You can't answer the question without this:

           "1 watt"
means
           "1 joule of energy, generated, used, or moved, every second".

So      60 watts  =  60 joules per second

           Total energy generated,
            used, or moved                  = (power) x (time).

                                     580 joules  =  (60 watts) x (time)

Divide each side
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                                               =  (9 and 2/3)  seconds  .
7 0
3 years ago
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