Hey can you please help me posted picture of question

Mathematics

1 answer:

lisov135 [29]3 years ago

5 0

If you observe the graph, the graph is touching the x-axis at the point x=-1 and is turning away.

This means, the graph as an even multiplicity at x=-1. So the two roots of the given polynomial are x = -1 and x = -1. Thus, the two factors of the polynomial are (x+1) and (x+1)

Product of the factors is equal to the polynomial. So the given polynomial will be (x+1)(x+1).

Therefore, the answer to this question is option C

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I need helping answering 15. I need to create a table and graph the function.

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ANSWER and EXPLANATION

We want to order the functions from widest to narrowest:

$\begin{gathered} y=3x^2 \\ y=2x^2 \\ y=4x^2 \end{gathered}$

To do this, we have to plot the graphs of the functions by using a table of values.

Let us find the values of the functions for values of x = -2, 0, 2

For the first function:

$\begin{gathered} y=3x^2 \\ \Rightarrow x=-2: \\ y=3(-2)^2=3*4 \\ y=12 \\ \Rightarrow x=0: \\ y=3(0)^2=3*0 \\ y=0 \\ \Rightarrow x=2: \\ y=3(2)^2=3*4 \\ y=12 \end{gathered}$

Hence, its table is:

For the second function:

$\begin{gathered} y=2x^2 \\ \Rightarrow x=-2: \\ y=2(-2)^2=2*4 \\ y=8 \\ \Rightarrow x=0: \\ y=2(0)^2=2*0 \\ y=0 \\ \Rightarrow x=2: \\ y=2(2)^2=2*4 \\ y=8 \end{gathered}$

Hence, its table is:

For the third function:

$\begin{gathered} y=4x^2 \\ \Rightarrow x=-2: \\ y=4\left(-2\right)^2=4*4 \\ y=16 \\ \Rightarrow x=0: \\ y=4(0)^2=4*0 \\ y=0 \\ \Rightarrow x=2: \\ y=4(2)^2=4*4 \\ y=16 \end{gathered}$

Hence, its table is:

Now, let us plot the graphs of the functions:

Therefore, from the graph, we see that the order of the functions from widest to narrowest is: