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4 years ago

Hey can you please help me posted picture of question

Mathematics

1 answer:

lisov135 [29]4 years ago

5 0

If you observe the graph, the graph is touching the x-axis at the point x=-1 and is turning away.

This means, the graph as an even multiplicity at x=-1. So the two roots of the given polynomial are x = -1 and x = -1. Thus, the two factors of the polynomial are (x+1) and (x+1)

Product of the factors is equal to the polynomial. So the given polynomial will be (x+1)(x+1).

Therefore, the answer to this question is option C

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How do you find the missing height of a trapezoid

IRISSAK [1]

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3 years ago

Can anyone help me fast?

Yanka [14]

Answer:

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3 years ago

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Mice21 [21]

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3 years ago

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saul85 [17]

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6 0

3 years ago

A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v>=2i-4tj^

guapka [62]

Given :

A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .

To Find :

A. The vector position of the particle at any time t .

B. The acceleration of the particle at any time t .

Solution :

A )

Position of vector v is given by :

$d=\int\limits {v} \, dt\\\\d=\int\limits {(2i-4tj)} \, dt \\\\d=(2t)i+\dfrac{4t^2}{2}j\\\\d=(2t)i+(2t^2)j$

B )

Acceleration a is given by :

$a=\dfrac{dv}{dt}\\\\a=\dfrac{2i-4tj}{dt}\\\\a=\dfrac{2i}{dt}-\dfrac{4tj}{dt}\\\\a=0-4j\\\\a=-4j$

Hence , this is the required solution .

5 0

3 years ago