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3 years ago

8

Which term best describes what Donna observed? A:dew B:fog C:mist D:rain

1 answer:

MariettaO [177]3 years ago

6 0

I also think it’s B but not quite sure

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What is the main difference between a proton and a neutron?

Olenka [21]

I’m pretty sure it’s B since ones charge the neutral while ones is positive, it’s an obvious difference as well/

5 0

2 years ago

Read 2 more answers

What are the number of protons, electrons, and neutrons in one atom of titanium?.

Olin [163]

Answer:

Protons: 22

Neutrons: 26
Electrons: 22

Explanation:

Titanium's atomic number is 22, meaning that the number of protons it has in its nucleus is also 22. # of electrons = # of protons, so the number of electrons is also 22. Titanium has an atomic mass of 47.867, but we can round up to 48. To find the atomic mass, we add up number of protons and neutrons. We know the number of protons as 22, so we subtract 22 from 48 and get a number of 26. Thus, the number of neutrons is 26.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

3 0

2 years ago

What is the chemical formula of the following compound

OLga [1]

A. C3H10 is the answer

6 0

3 years ago

If you combine 230.0 mL 230.0 mL of water at 25.00 ∘ C 25.00 ∘C and 120.0 mL 120.0 mL of water at 95.00 ∘ C, 95.00 ∘C, what is t

Thepotemich [5.8K]

<u>Answer:</u> The final temperature of the mixture is 49°C

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

<u>For cold water:</u>

Density of cold water = 1 g/mL

Volume of cold water = 230.0 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{230.0mL}\\\\\text{Mass of water}=(1g/mL\times 230.0mL)=230g$

<u>For hot water:</u>

Density of hot water = 1 g/mL

Volume of hot water = 120.0 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{120.0mL}\\\\\text{Mass of water}=(1g/mL\times 120.0mL)=120g$

When hot water is mixed with cold water, the amount of heat released by hot water will be equal to the amount of heat absorbed by cold water.

$Heat_{\text{absorbed}}=Heat_{\text{released}}$

The equation used to calculate heat released or absorbed follows:

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]$ ......(1)

where,

q = heat absorbed or released

$m_1$ = mass of hot water = 120 g

$m_2$ = mass of cold water = 230 g

$T_{final}$ = final temperature = ?°C

$T_1$ = initial temperature of hot water = 95°C

$T_2$ = initial temperature of cold water = 25°C

c = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

$120\times 4.186\times (T_{final}-95)=-[230\times 4.186\times (T_{final}-25)]$

$T_{final}=49^oC$

Hence, the final temperature of the mixture is 49°C

4 0

3 years ago

Which component is soluble in water

Vesna [10]

Answer:

salt

Explanation:

6 0

3 years ago