Answer:
1 to 696
The expansion ratio of liquefied and cryogenic from the boiling point to ambient is: nitrogen 1 to 696. liquid helium 1 to 757. argon 1 to 847.
Explanation:
Answer:
0.628 M.
Explanation:
In order to solve this problem we need to keep in mind the<em> definition of molarity</em>:
- Molarity = moles / liters
We are given both the <em>number of moles and the volume of solution</em>, meaning we can now proceed to <u>calculate the molarity</u>:
- Molarity = 0.220 mol / 0.350 L
Answer:
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Explanation:
Thank you for posting your question here. Below is the solution:
HNO3 --> H+ + NO3-
<span>HNO3 = strong acid so 100% dissociation </span>
<span>** one doesn't need to find the molarity of water since it is the solvent </span>
<span>0M HNO3 </span>
<span>1x10^-6M H3O+ </span>
<span>1x10^-6M NO3- </span>
<span>1x10^-8M OH-.....the Kw = 1x10^-14 = [H+][OH-] </span>
<span>you have 1x10^-6M H+ so, 1x10^-14 / 1x10^-6 = 1x10^-8M OH- </span>
<span>1x10^-6 Ba(OH)2 = strong base, 100% dissociation </span>
<span>1x10^-6M Ba2+ </span>
<span>2x10^-6M OH- since there are 2 OH- / 1 Ba2+ </span>
<span>0M Ba(OH)2 </span>
<span>5x10^-9M H3O+</span>
