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2 years ago

How many atoms are in 85.1 grams of neon

1 answer:

7 0

Convert the mass to moles .

85.1 g ÷ 20.18 g/mol = 4.21704658

convert the moles to molecules

4.2170 mol × 6.022^23 molecules/mol = 2.539^24

You might be interested in

. One mole of N2O4 contains ___________.

ivanzaharov [21]

One molecule of N2O4 contains

two nitrogen
four oxygen

7 0

2 years ago

A certain reaction at equilibrium has more moles of gaseous products than of gaseous reactants.(b) Write a statement about the r

mojhsa [17]

To be equal as $K_p$ , $K_c$ needs to be divided by $(RT)^{\Delta n}$

<h3>Briefly explained</h3>

When the amount of gaseous reactant is greater than the amount of gaseous product, where $n_{products} < n_{reactants}$ ,

then = $K_p < K_c$

It's because $\Delta n$ is negative, which places (RT) in the denominator. This is how the equation will now appear.

$K_p = K_c(RT)^{-\Delta n} = \frac{ K_c}{(RT)^{\Delta n}}$

Here you can observe the value of $K_c$ is greater than $K_p$ . To be equal as $K_p$ , $K_c$ needs to be divided by $(RT)^{\Delta n}$

<h3>What is Δngas?</h3>

The number of moles of gas that move from the reactant side to the product side is denoted by the symbol ∆n or delta n in this equation.

Once more, n represents the growth in the number of gaseous molecules the equilibrium equation can represent. When there are exactly the same number of gaseous molecules in the system, n = 0, Kp = Kc, and both equilibrium constants are dimensionless.

<h3>Definition of equilibrium</h3>

When a chemical reaction does not completely transform all reactants into products, equilibrium occurs. Many chemical processes eventually reach a state of balance or dynamic equilibrium where both reactants and products are present.

Learn more about equilibrium

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6 0

1 year ago

Assume that 8.5 L of iodine gas (I2) are produced at STP according to the following balanced equation:2KI(aq) + Cl2(

Aliun [14]

Answer: 0.3794 moles of Iodine gas are produced.

Explanation:

$2KI(aq)+Cl_2(
g)\rightarrow 2KCl(aq)+I_2$

Volume of iodine gas produced at STP =8.5 L

At STP, the 1 mol of gas occupies volume = 22.4 L

So, 8.5 L of volume will be occupied by: $\frac{1}{22.4 L}\times 8.5=0.3794 moles$

0.3794 moles of Iodine gas are produced.

5 0

3 years ago

Read 2 more answers

A 250-ml sample of na2so4 is reacted with an excess of bacl2. if 5.28 g baso4 is precipitated, what is the molarity of the na2so

Oksanka [162]

To get the molarity you need to follow this equation
moles of solute
Molarity (M = -----------------------
Liters of solution

But before you apply that equation you need to find the moles of solute and the liters of solution. Follow this equation

Na2SO4 + BaCl2 = BaSO4 + 2 NaCl

Solution

Moles of BaSO4 = 5.28 g
---------------
233.43 g / mol
= 0.0226 moles
Moles of NaSO4 = 0.0226
0.0226 mole
Molarity = -----------------
0.250 L
= 0.0905 mol / L

So the answer is 0.0905 mol / L

3 0

2 years ago

Name the functional group in the

vodomira [7]

Answer:

aldehyde

Explanation:

8 0

3 years ago