C) a cube that measures one metre on each side
Answer:
m/min
Explanation:
You have to use the volume of a cone, which is:
where r is the radius of the base and h is the height.
In this case, r=5 and h=10. The radius can be written as r=h/2
Replacing it in the equation:
(I)
The rate of the volume is the derivate of volume respect time, therefore you have to perform the implicit differentiation of the previous equation and equal the result to 3.14 m³/min
Replacing dV/dt= 3.14, h=7.5 and solving for dh/dt, which represents how fast the level is rising:
Multiplying by 16/225π both sides:
m/min
Answer:
Hello your question is poorly written below is the complete question
Suppose the battery in a clock wears out after moving Ten thousand coulombs of charge through the clock at a rate of 0.5 Ma how long did the clock run on does battery and how many electrons per second slowed?
answer :
a) 231.48 days
b) n = 3.125 * 10^15
Explanation:
Battery moved 10,000 coulombs
current rate = 0.5 mA
<u>A) Determine how long the clock run on the battery. use the relation below</u>
q = i * t ----- ( 1 )
q = charge , i = current , t = time
10000 = 0.5 * 10^-3 * t
hence t = 2 * 10^7 secs
hence the time = 231.48 days
<u>B) Determine how many electrons per second flowed </u>
q = n*e ------ ( 2 )
n = number of electrons
e = 1.6 * 10^-19
q = 0.5 * 10^-3 coulomb ( charge flowing per electron )
back to equation 2
n ( number of electrons ) = q / e = ( 0.5 * 10^-3 ) / ( 1.6 * 10^-19 )
hence : n = 3.125 * 10^15
Let h = the thickness of ice, m.
Because the ice covers an area of 0.65 m², the volume of ice is
V = 0.65h m³
The density of ice is 917 kg/m³, therefore the mass of ice is
m = (917 kg/m³)*(0.65h m³) = 596.05h kg
The latent heat of fusion of ice is 3.35 x 10⁵ J/kg, therefore the heat required to melt the ice is
Q₁ = (596.05h kg)*(3.35 x 10⁵ J/kg) = 2h x 10⁸ J
The electric heater supplies heat at 12 V, 23 A for 4.3 minutes to melt the ice.
Therefore the heat provided is
Q₂ = (12 V)*(23 A)*(4.3*60 s) = 71208 J
Because Q₁ = Q₂, obtain
2h x 10⁸ = 71208
h = 356 x 10⁻⁶ m = 356 x 10⁻³ mm = 0.356 mm
Answer: 0.356 mm