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ololo11 [35]
3 years ago
8

An 100W light bulb is on 6 hours work out the energy (kWh) used and the cost of it (1kWh = £0.1359) with working out please

Physics
1 answer:
Ainat [17]3 years ago
8 0
1,000 W  =  1 kW
100 W  =  0.1 kW

           (0.1 kW) x (6 h) = 0.6 kWh    <=== energy

           (0.6 kWh) x (£0.1359/kWh)  =  £0.0815     <=== cost of it     
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The Luminosity of a star is proportional to its Effective Temperature to the 4th power and its Radius squared.
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3 years ago
A block of mass m is pushed up against a spring, compressing it a distance x, and the block is then released. The spring project
Gwar [14]

Answer:

x' = 10 x

Explanation:

By energy conservation we know that spring energy is converted into kinetic energy of the block

so we will have

\frac{1}{2}kx^2 = \frac{1}{2}mv^2

so we will have

v = \sqrt{\frac{k}{m}}(x)

now we will have same thing for another mass 4m which moves out with speed 5v

so we have

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now from above two equations we have

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so we have

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blondinia [14]

When an object falls from a h height, you should work with the uniformly accelerated linear movement equations:

y=½*a*t²+Vo*t+yo

You should consider:

a=-g=-10m/s²

yo=h

If it’s a freefall, it means it starts from rest, which means it has no initial velocity:

Vo=0

Replacing that information in the equation:

y=½*(-10m/s²)*t²+0*t+h=-5m/s²*t²+0+h=-5m/s²*t²+h

So this is the

Besides, if you want to find out how long it takes for it to get to the floor, you should put the height of the floor as final height, which would be 0 (assuming the initial height has been measured from there):

y=0

0=-5m/s²*t²+h

5m/s²*t²=h

t²=h/(5m/s²)

t=√(h/(5m/s²))

t=√(hs²/(5m))

t=(√(h/(5m)))s

<span>If we <span>quadruple </span>h:</span>

t2=(√(h2/(5m)))s=(√(4*h1/(5m)))s=(√4)*(√h1/(5m)))s=2*(√h1/(5m)))s=2*t1

This 4 goes inside the square root, so then it converts to 2. So the new time is twice as much the previous time.

Concerning velocity, you have to use the other equation:

v=at+vo

As I said before, a is gravity and vo is zero.

v=-10m/s²*t+0=-10m/s²*t

Final velocity is directly related to time, so if time is doubled, so is velocity.

v2=-10m/s²*t2=-10m/s²*(2*t1)=2*(-10m/s²*t1)=2*v1

<span>So the correct answer is A, and the other ones are false.</span>

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