Question

An object is moving at a velocity of 3m/s. It accelerates to a velocity of 5.5m/s over a time of 9 s. What acceleration did it experience?

Answer 1

Answer:

Acceleration(a) = $\displaystyle\frac{v - u}{t}$

v = final velocity = 5.5 m/s

u = initial velocity = 3 m/s

t = time = 9s

$\displaystyle a = \frac{3-5.5}{9}$

$a = \displaystyle\frac{-2.5}{9}$

$a = -0.278 \ m/s^2$ (approx)