.Which uplift mechanism is pictured here?

Physics

2 answers:

zhenek [66]4 years ago

4 0

The correct answer is orographic uplift! Hope this helps

Natasha_Volkova [10]4 years ago

3 0

Answer: B. orographic uplift

Explanation:-

When air is collided by mountains, it cannot passes through them.

Since the air rises up the mountain, the air cools down as it rises .

If air cools to its saturation point, the water vapor condenses to form clouds.

These clouds are develop in response to the lifting forced by the topography the earth. Therefore, they are called called orographic clouds.

Hence, the called orographic clouds, which is orographic uplift.

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Can someone please help me and write the answers? i need this and it’s really important!!

eduard

-- Kinetic energy is the energy of mass in motion. The amount is determined by the mass of whatever is moving, and its speed.

-- Potential energy is the energy that's stored up in some form, not being used yet but ready to be used when you want it.

For example, one form of it is chemical potential energy, like in a battery, or a match. You get the energy out of a battery when you connect it to a motor or a light. You get the energy out of as match when you make the tip hot and it flares up.

This question is asking about gravitational potential energy. An object has stored energy just by being up high, like a bowling ball on a shelf. You get the energy out of it just by dropping it ... possibly enough to crack the floor !

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5 0

4 years ago

miniature spring-loaded, radio-controlled gun is mounted on an air puck. The gun's bullet has a mass of 5.00 g, and the gun and

Tamiku [17]

Answer:

12 m/s

Explanation:

From the question,

Applying the law of conservation of momentum,

total momentum before collision = Total momentum after collision

mu+Mu' = mv+Mv'........................... Equation 1

Where m = mass of the bullet, u = initial velocity of the bullet, M = combined mass of the gun and the puck, u' = initial velocity of the gun and the puck, v = final velocity of the bullet, v' = final velocity of the gun and the puck

make v the subeject of the equation

v = [(mu+Mu')-Mv']/m................. Equation 2

Given: m = 5.00 g = 0.005 kg, M = 120 g = 0.12 kg, u = u' = 0 m/s (at rest), v' = 0.5 m/s

Substitute these values into equation 2

v = [0-(0.12×0.5)]/0.005

v = -0.06/0.005

v = -12 m/s

The negative sign can be ignored since we are looking for the speed, which has only magnitude.

Hence the speed of the bullet is 12 m/s

5 0

3 years ago

During physical science class, ben and jerry connected three identical light bulbs in parrallel to a battery. What happens when