If the frequency of a sound wave is 990 Hz, calculate its wavelength.

A particle moves along a straight line with equation of motion s = f(t), where s is measured in meters and t in seconds. Find th

Rashid [163]

Answer:

The velocity of the particle = -1.92 m/s

The speed of the particle = 5.72 m/s

Explanation:

Given equation of motion;

$f(t) = 18 \ + \ \frac{48}{t} \ + \ 1$

Velocity is defined as the change in displacement with time.

$V = \frac{df(t)}{dt} = -\frac{48}{t^2} \\\\at \ t = 5 \ s\\\\V = -\frac{48}{5^2} = \frac{-48}{25} = - 1.92 \ m/s$

The distance traveled by the particle in 5 s:

$s = f(5) = 18 + \frac{48}{5} + 1\\\\s= 28.6 \ m$

The speed of the particle when t = 5s

$Speed = \frac{28.6}{5} = 5.72 \ m/s$

6 0

3 years ago

A body travels the first half of the total distance with velocity v and second half with v2 calculate avg velocity

LuckyWell [14K]

Answer:

v = 2 v₁ v₂ / (v₁ + v₂)

Explanation:

The body travels the first half of the distance with velocity v₁. The time it takes is:

t₁ = (d/2) / v₁

t₁ = d / (2v₁)

Similarly, the body travels the second half with velocity v₂, so the time is:

t₂ = (d/2) / v₂

t₂ = d / (2v₂)

The average velocity is the total displacement over total time:

v = d / t

v = d / (t₁ + t₂)

v = d / (d / (2v₁) + d / (2v₂))

v = d / (d/2 (1/v₁ + 1/v₂))

v = 2 / (1/v₁ + 1/v₂)

v = 2 / ((v₁ + v₂) / (v₁ v₂))

v = 2 v₁ v₂ / (v₁ + v₂)

8 0

3 years ago

Coherent light with wavelength = 600 nm falls on two very narrow closely spaced slits and the interference pattern is observed o

Mrac [35]

Answer:

The distance between the two slits is 1.2mm.

Explanation:

The physicist Thomas Young establishes, through its double slit experiment, a relationship between the interference (constructive or destructive) of a wave, the separation between the slits, the distance between the two slits to the screen and the wavelength.

$\Lambda x = L\frac{\lambda}{d}$ (1)

Where $\Lambda x$ is the distance between two adjacent maxima, L is the distance of the screen from the slits, $\lambda$ is the wavelength and d is the separation between the slits.

If light pass through two slits a diffraction pattern in a screen will be gotten, at which each bright region corresponds to a crest, a dark region to a trough, as consequence of constructive interference and destructive interference in different points of its propagation to the screen.

Therefore, d can be isolated from equation 1.

$d = L\frac{\lambda}{\Lambda x}$ (2)