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mr_godi [17]
3 years ago
14

A particle travels in a straight line with speed v.

Physics
2 answers:
alexandr402 [8]3 years ago
8 0

Answer:

D 60°

Explanation:

Using trigonometry:

- The new speed (v/2) of the particle corresponds to the hypothenuse

- The component of v/4 represents the side adjacent  to the angle that we want fo find, \theta

So we can write:

cos \theta = \frac{adjacent}{hypothenuse}=\frac{v/4}{v/2}=\frac{1}{2}

So we find the angle

\theta= cos^{-1} (\frac{1}{2})=60^{\circ}

Elan Coil [88]3 years ago
3 0

Answer:

D 60°

Explanation:

Using trigonometry in the attached image:

cos\alpha =\frac{v/4}{v/2}

cos\alpha =\frac{1}{2}

\alpha =cos^{-1} \frac{1}{2}

Angle=60°

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A car is traveling at 40 m/s for 20 seconds. How far did it travel in this time?
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<h3>Answer:</h3>

800 meters

<h3>Explanation;</h3>

<u>We are given;</u>

  • Speed as 40 m/s
  • Time as 20 seconds

We are required to determine the distance traveled

  • Speed refers to the rate of change in distance.
  • It is given by;

Speed = Distance ÷ time

Rearranging the formula;

Distance = speed × time

In this case;

Distance = 40 m/s × 20 sec

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Thus, the distance traveled by the car is 800 m

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3 years ago
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1. Eat a balanced diet and regular exercise. This is the best way because eating right and exercising are is more beneficial than just exercising.
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If a nearsighted person has a far point df that is 3.50m from the eye, what is the focal length f1 of the contact lenses that th
olga55 [171]

Answer:

f1= -350cm or -3.5m

f2= 22.1cm or 0.221m

Explanation:

A person is nearsighted when the person's far point is less than infinity. A diverging lens is normally used to correct this eye defect. A diverging lens has a negative focal length as seen in the solution attached.

Farsightedness is when a person's near point is farther than 25cm. This eye defect is corrected using a converging lens. The focal length of a converging lens is positive. This is evident in the solution attached. The near point is also referred to as the least distance of distinct vision.

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The ear drum vibrates when struck by sound waves and directly sends a message to the brain that is then recognized as sound
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Answer:

true

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3 years ago
A student stretches a spring, attaches a 1.20 kg mass to it, and releases the mass from rest on a frictionless surface. The resu
Sphinxa [80]

Answer:

the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

Explanation:

Given that;

mass of the object m = 1.20 kg

period of oscillation = 0.750 s

Amplitude ( A/x) = 15.0 cm = 0.15 m

now;

a) Determine the oscillation frequency;

oscillation frequency f = 1/T

we substitute

f = 1 / 0.750 s

f = 1.33 Hz

Therefore, the oscillation frequency is 1.33 Hz

b) Determine the spring constant;

we solve for spring constant from the following expression;

T = 2π√(m/k)

k = 4π²m / T²

so we substitute

k = (4π² × 1.20) / (0.750)²

k = 47.3741 / 0.5625

k =  84.22 N/m

Therefore, the spring constant is 84.22 N/m

c) determine the speed of the mass when it is halfway to the equilibrium position

So, at equilibrium, the energy is equal to K.E

such that;

1/2mv² = 1/2kx²

mv² = kx²

v² = kx² / m

v = √( kx²/m)

we substitute

v = √( 84.22×(0.15 m)²/ 1.2 )

v = √( 1.89495 / 1.2 )

v = √ 1.579125

v = 1.26 m/s  

Therefore, the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

3 0
3 years ago
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