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mr_godi [17]
3 years ago
14

A particle travels in a straight line with speed v.

Physics
2 answers:
alexandr402 [8]3 years ago
8 0

Answer:

D 60°

Explanation:

Using trigonometry:

- The new speed (v/2) of the particle corresponds to the hypothenuse

- The component of v/4 represents the side adjacent  to the angle that we want fo find, \theta

So we can write:

cos \theta = \frac{adjacent}{hypothenuse}=\frac{v/4}{v/2}=\frac{1}{2}

So we find the angle

\theta= cos^{-1} (\frac{1}{2})=60^{\circ}

Elan Coil [88]3 years ago
3 0

Answer:

D 60°

Explanation:

Using trigonometry in the attached image:

cos\alpha =\frac{v/4}{v/2}

cos\alpha =\frac{1}{2}

\alpha =cos^{-1} \frac{1}{2}

Angle=60°

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Two steamrollers begin 105 mm apart and head toward each other, each at a constant speed of 1.20 m/s. At the same instant, a fly
levacccp [35]

Answer: 109.4 mm

Explanation: <u>Distance</u> is a scalar quantity and it is the measure of how much path there are between two locations. It can be calculated as the product of velocity and time:  d = vt

The separation between the two steamrollers is 105 mm or 0.105 m. They collide to each other at the middle of the separation:

location of collision = \frac{0.105}{2} = 0.0525 m

To reach that point, both steamrollers will have spent

v=\frac{\Delta x}{t}

t=\frac{\Delta x}{v}

t=\frac{0.0525}{1.2}

t = 0.04375 s

The fly is travelling with speed of 2.5 m/s. So, at t = 0.04375 s:

d = 2.5*0.04375

d = 0.109375 m

Until it is crushed, the fly will have traveled 109.4 mm.

4 0
3 years ago
A marble dropped in still water will create circular ripples or waves. the radius of each circular wave will increase 4 centimet
Gnom [1K]

The circumference of the circle after t seconds = 25.12 t

Given data,

The radius of each circular wave will increase by four centimeters per second (cm/s)

In 1 second of circular wave radius = 4cm

In 1*t second of circular wave radius = 4t cm

 

As a result, the radius of the circular wave after t seconds is 4t cm.

We already know that the circumference of a circle is given by = 2πr, where r is the circle's radius.

As a result, the radius of a circular wave after t seconds is = 2π * radius of a circular wave after t seconds = 2π * 4t

                                                    = 8πt

( Taking π = 3.14 )

As a result, the circumference of the circle after t seconds = 8πt

                                                                                                     = 3.14t

                                                                                                   = 25.12t

Find more on circumference at : brainly.in/question/49774764

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5 0
2 years ago
The area of the piston to the master cylinder in a hydraulic braking system of a car is 0.4 square inches. If a force of 6.4 lb
Anit [1.1K]

Answer:

The force applied on one wheel during braking = 6.8 lb

Explanation:

Area of the piston (A) = 0.4 in^{2}

Force applied on the piston(F) = 6.4 lb

Pressure on the piston (P) = \frac{F}{A}

⇒ P = \frac{6.4}{0.4}

⇒ P = 16 \frac{lb}{in^{2} }

This is the pressure inside the cylinder.

Let force applied on the brake pad = F_{1}

Area of the brake pad (A_{1})= 1.7 in^{2}

Thus the pressure on the brake pad (P_{1}) =  \frac{F_{1} }{A_{1} }

When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.

⇒ P = P_{1}

⇒ 16 = \frac{F_{1} }{A_{1} }

⇒ F_{1} = 16 × A_{1}

Put the value of A_{1} we get

⇒ F_{1} = 16 × 1.7

⇒ F_{1} = 27.2 lb

This the total force applied during braking.

The force applied on one wheel = \frac{F_{1} }{4} = \frac{27.2}{4} = 6.8 lb

⇒ The force applied on one wheel during braking.

7 0
3 years ago
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olasank [31]
A) P = 75 \times (2.7\times10^7) = 2.025\times10^9 W

b) Efficiency =  \frac{8\times10^8}{2.025\times10^9} \times 100 \approx 39.5\%
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Mira is much bigger than the Sun.

Only very massive stars will go through a supernova stage, causing the outer layer to explode away and the core to collapse in on itself, becoming very dense.

5 0
2 years ago
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