The answer is a cation, I may be wrong but cation is plus and anion is subtract
Answer:
3)The reaction is not at equilibrium and willproceed to the right.
Explanation:
The reaction quotient of an equilibrium reaction measures relative amounts of the products and the reactants present during the course of the reaction at particular point in the time.
It is the ratio of the concentration of the products and the reactants each raised to their stoichiometric coefficients. The concentration of the liquid and the gaseous species does not change and thus is not written in the expression.
Q < Kc , reaction will proceed in forward direction.
Q > Kc , reaction will proceed in backward direction.
Q = Kc , reaction at equilibrium.
Given that:
Q = 
K = 
Since, Q < K , reaction is not at equilibrium and will proceed to right, in forward direction.
Solution is here,
for initial case,
temperature(T1)=70°C=70+ 273=343K
vloume( V1) =45 L
for final case,
temperature( T2)=?
volume(V2)= 91.3 L
at constant pressure,
V1/V2 = T1/T2
or, 45/91.3 = 343/ T2
or, T2= (343×91.3)/45
or, T2=695.9 K = (695.9-273)°C=422.9°C
Answer:
D.
Explanation:
Although all of these answers are similar, it seems that all three are the answer. I am sorry if the answer ends up being B but I'm pretty sure the answer is D. Charles Darwin's evolution theory "evolved", get it, from the natural selection theory. The theory is described as "the process whereby organisms better adapted to their environment tend to survive and produce more offspring." However, some factors that effect natural selection are competition, selection and variation. I believe all three fit the answer and therefore I believe answer D is correct.
The type of bond between two elements can be predicted by measuring the electronegativity difference between the two atoms. Based on this difference the type of bonds are classified as,
E.N difference between 0.0 to 0.3 = Non Polar bond
E.N difference between 0.4 to 1.0 = Moderate Polar Covalent Bond
E.N difference between 1.1 to 2.0 = Very Polar Covalent Bond
E.N difference greater than 2.0 = Ionic Bond
So,
(E.N of N) 3.04 - (E.N of C) 2.55 = 0.49
As the difference is between 0.4-1.0, So, the bond between C and N is Moderate Polar Covalent Bond (or Polar Covalent Bond).
