Mass of methanol (CH3OH) = 1.922 g
Change in Temperature (t) = 4.20°C
Heat capacity of the bomb plus water = 10.4 KJ/oC
The heat absorbed by the bomb and water is equal to the product of the heat capacity and the temperature change.
Let’s assume that no heat is lost to the surroundings. First, let’s calculate the heat changes in the calorimeter. This is calculated using the formula shown below:
qcal = Ccalt
Where, qcal = heat of reaction
Ccal = heat capacity of calorimeter
t = change in temperature of the sample
Now, let’s calculate qcal:
qcal = (10.4 kJ/°C)(4.20°C)
= 43.68 kJ
Always qsys = qcal + qrxn = 0,
qrxn = -43.68 kJ
The heat change of the reaction is - 43.68 kJ which is the heat released by the combustion of 1.922 g of CH3OH. Therefore, the conversion factor is:
D. the potential energy of the reactants is low; the potential energy decreases gradually; then increases slightly.
Answer:
Mass in nuclear reactions is not strictly conserved due to this principle of mass and energy being quite similar. We know that nuclear reactions release a lot of energy. This energy, though, is actually mass that is lost from nucleons, converted into energy, and lost as the mass defect.
Some mass is turned into energy, according to E=mc2.
<em><u>Explanation:</u></em>
E=mc2 is probably the most famous equation. E is the energy, m is mass, and c is the constant speed of light. Einstein came up with it to show that energy and mass are proportional - one can turn into the other, and back again.
Mass in nuclear reactions is not strictly conserved due to this principle of mass and energy being quite similar. We know that nuclear reactions release a lot of energy. This energy, though, is actually mass that is lost from nucleons, converted into energy, and lost as the mass defect.
Answer:
B
Explanation:
When water is at the surface of the ground, it evaporates and goes back to the clouds for which causes it to rain therefore returning water back.
