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natali 33 [55]
2 years ago
14

Explain how atoms organize to create larger structures?

Chemistry
1 answer:
Mrrafil [7]2 years ago
6 0

Answer:

First of all they are super tiny particles of neutrons, electrons and protons. Then they come together to organize a structure of atom. Atoms come together to form a molecule and smaller molecules work together to form macromolecules. Thus, how they organize and form building blocks of a substance.

Hope it helps!<3

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Consider this question: What is the molarity of HCL if 35.23 mL of a solution of HCL contains 0.3366 g of HCL?
Crazy boy [7]

<u>Answer:</u> The molarity of HCl solution is 0.262 M

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Given mass of HCl = 0.3366 g

Molar mass of HCl = 36.5 g/mol

Volume of the solution = 35.23 mL

Putting values in above equation, we get:

\text{Molarity of HCl}=\frac{0.3366g\times 1000}{36.5g/mol\times 35.23mL}\\\\\text{Molarity of HCl}=0.262M

Hence, the molarity of HCl solution is 0.262 M.

6 0
2 years ago
Which substance is important in making plastics?
QveST [7]
Based on the compounds given, I can say that the substance that is considered essential in the plastic making is NITRIC ACID. This substance is also known as aqua fortis and spirit of niter wherein this decomposes into oxides of nitrogen and water. The answer would be the last option. Hope this helps.
8 0
3 years ago
Read 2 more answers
6) 3.2 grams of sodium chloride is dissolved to make 0.25 liters of solution. Hint Convert grams to moles first! Molar mass of N
otez555 [7]

Which solution is the least concentrated?

O 2 moles of solute dissolved in 4 liters of solution

5 0
2 years ago
1. Calculate the energy change (q) of the surroundings (water) using the enthalpy equation
Rasek [7]

Answer:

Q1: 728.6 J.

Q2:

a) 668.8 J.

b) 0.3495 J/g°C.

Explanation:

<em>Q1: Calculate the energy change (q) of the surroundings (water) using the enthalpy equation:</em>

  • The amount of heat absorbed by water = Q = m.c.ΔT.

where, m is the mass of water (m = d x V = (1.0 g/mL)(24.9 mL) = 24.9 g).

c is the specific heat capacity of liquid water = 4.18 J/g°C.

ΔT is the temperature difference = (final T - initial T = 32.2°C - 25.2°C = 7.0°C).

<em>∴ The amount of heat absorbed by water = Q = m.c.ΔT</em> = (24.9 g)(4.18 J/g°C)(7.0°C) = 728.6 J.

<em>Q2:  Calculate the energy change (q) of the surroundings (water) using the enthalpy equation </em>

<em>qwater = m × c × ΔT.  </em>

<em>We can assume that the specific heat capacity of water is 4.18 J / (g × °C) and the density of water is 1.00 g/mL. calculate the specific heat of the metal. Use the data from your experiment for the unknown metal in your calculation.</em>

<em></em>

a) First part: the energy change (q) of the surroundings (water):

  • The amount of heat absorbed by water = Q = m.c.ΔT.

where, m is the mass of water (m = d x V = (1.0 g/mL)(25 mL) = 25 g).

c is the specific heat capacity of liquid water = 4.18 J/g°C.

ΔT is the temperature difference = (final T - initial T = 31.6°C - 25.2°C = 6.4°C).

<em>∴ The amount of heat absorbed by water = Q = m.c.ΔT</em> = (25 g)(4.18 J/g°C)(6.4°C) = <em>668.8 J.</em>

<em>b) second part:</em>

<em>Q water = Q unknown metal. </em>

<em>Q unknown metal =  - </em>668.8 J. (negative sign due to the heat is released from the metal to the surrounding water).

<em>Q unknown metal =  - </em>668.8 J = m.c.ΔT.

m = 27.776 g, c = ??? J/g°C, ΔT = (final T - initial T = 31.6°C - 100.5°C = - 68.9°C).

<em>- </em>668.8 J = m.c.ΔT = (27.776 g)(c)( - 68.9°C) = - 1914 c.

∴ c = (<em>- </em>668.8)/(- 1914) = 0.3495 J/g°C.

<em></em>

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3 years ago
Which data can be measured quantitatively?
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Quantitative numerical data
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