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stellarik [79]
3 years ago
13

The the heat system in a home most likely uses ________________ to transfer heat.

Chemistry
1 answer:
tino4ka555 [31]3 years ago
5 0
Radiation is the answer
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How do you increase the concentration of a solution wiki?
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It would be to change the amount of solute or solvent in the solution.
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3 years ago
I NEED THIS NOW PLEASE HELP ​
ad-work [718]

Answer:

photosynthesis

Explanation:

its the first step of the cycle

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3 years ago
Is burning of wood a reversible or irreversible change
nignag [31]

Answer:

burning of wood is an irreversible change bcoz wood after burning wood converted to ashes cannot be converted back to wood nd its chemical composition also changes

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4 years ago
Read 2 more answers
Kc for the reaction of hydrogen and iodine to produce hydrogen iodide.
tatiyna

Answer:

[H_2]_{eq}=0.183M

[I_2]_{eq}=0.183M

[HI]_{eq}=0.025M

Explanation:

Hello.

In this case, for this equilibrium problem, we first realize that at the beginning there is just HI, it means that the reaction should be rewritten as follows:

2HI\rightleftharpoons H_2+I_2

Whereas the law of mass action (equilibrium expression) is:

Kc=\frac{[H_2][I_2]}{[HI]^2}

That in terms of initial concentrations and reaction extent or change x turns out:

Kc=\frac{x*x}{([HI]_0-2x)^2}\\\\54.3=\frac{x^2}{(0.391M-2x)^2}

And the solution via solver or quadratic equation is:

x_1=0.183M\\\\x_2=0.210M

Whereas the correct answer is 0.183 M since the other value yield a negative concentration of HI at equilibrium (0.391-2*0.210=-0.029M).This, the equilibrium concentrations are:

[H_2]_{eq}=0.183M

[I_2]_{eq}=0.183M

[HI]_{eq}=0.391M-2*0.183M=0.025M

Regards.

6 0
3 years ago
The equilibrium constant for the chemical equation N2(g) + 3H2(g) ⇌ 2NH3(g) and Kp=0.174 at 243°C. Calculate the value of Kc for
Mashcka [7]

Answer:

The Kc of this reaction is 311.97

Explanation:

Step 1: Data given

Kp = 0.174

Temperature = 243 °C

Step 2: The balanced equation

N2(g) + 3H2(g) ⇌ 2NH3(g)

Step 3: Calculate Kc

Kp = Kc *(RT)^Δn

⇒ with Kp = 0.174

⇒ with Kc = TO BE DETERMINED

⇒ with R = the gas constant = 0.08206 Latm/Kmol

⇒ with T = the temperature = 243 °C = 516 K

⇒ with Δn = number of moles products - moles reactants  2 – (1 + 3) = -2

0.174 = Kc (0.08206*516)^-2

Kc = 311.97

The Kc of this reaction is 311.97

3 0
3 years ago
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