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3 years ago

What reaction is depicted by the given equation: au3 3e− au

1 answer:

3 0

This is a reduction half-reaction. Initially, gold exists as $Au^{3+}$ , and after the reaction, it has been converted to elemental gold. To make this possible, three electrons must be added to $Au^{3+}$ . This fits within the definition of reduction reactions, where the reactant gains electrons in the reaction.

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The Earth's diameter at the equators is _____ its diameter at the poles. A:greater than B:equal to C:less than

Svetlanka [38]

I think the answer is greater than

7 0

2 years ago

Name three machines which convert straight motion to circular motion.

fgiga [73]

A Grinder,A Mixer,A Car

3 0

3 years ago

Which term best describes this reaction? 2 carbons double bonded to each other, with CH 3 above the left C and H above the right

Ierofanga [76]

Answer:

addition polymerization

Explanation:

In addition polymerization, the monomers are simply joined to each other to form a polymer having the same empirical formula as the monomer but of higher relative molecular mass. The monomers in addition polymerization are usually simple unsaturated molecules such as alkenes.

We can deduce the reaction to be an addition polymerization because of the the attachment of n to both the unsaturated monomer and the saturated polymer without the loss of any small molecule. If it was a condensation polymerization, there would have been an accompanying loss of a small molecule such as water.

6 0

3 years ago

How many ml of a 0.50m solution of hno3 solution are needed to make 500 ml of 0.15m hno3

Anna71 [15]

Answer:

150.0 mL.

Explanation:

It is known that the no. of millimoles of HNO₃ before dilution = the no. of millimoles of HNO₃ after dilution.

∵ (MV) before dilution = (MV) after dilution.

∴ V before dilution = (MV) after dilution / M before dilution = (0.15 M)(500.0 mL)/(0.50 M) = 150.0 mL.

7 0

2 years ago

If you have 16 g of manganese (II) nitrate tetrahydrate, how much water is required to prepare 0.16 M solution from this amount

Schach [20]

Answer: The amount of water required to prepare given amount of salt is 398.4 mL

Explanation:

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.16 M

Given mass of manganese (II) nitrate tetrahydrate = 16 g

Molar mass of manganese (II) nitrate tetrahydrate = 251 g/mol

Putting values in above equation, we get:

$0.16M=\frac{16\times 1000}{251\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{16\times 1000}{251\times 0.16}=398.4mL$

Volume of water = Volume of solution = 398.4 mL

Hence, the amount of water required to prepare given amount of salt is 398.4 mL

4 0

3 years ago