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yanalaym [24]
3 years ago
10

What reaction is depicted by the given equation: au3 3e− au

Chemistry
1 answer:
mrs_skeptik [129]3 years ago
3 0
This is a reduction half-reaction. Initially, gold exists as Au^{3+}, and after the reaction, it has been converted to elemental gold. To make this possible, three electrons must be added to <span>Au^{3+}. This fits within the definition of reduction reactions, where the reactant gains electrons in the reaction.</span>
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Explain the process of photosynthesis.
ra1l [238]

Answer:

During photosynthesis, plants take in carbon dioxide (CO2) and water (H2O) from the air and soil. This transforms the water into oxygen and the carbon dioxide into glucose. The plant then releases the oxygen back into the air, and stores energy within the glucose molecules.

Explanation:

Brainliest please

5 0
3 years ago
Nitric acid can be produced by the reaction of gaseous nitrogen dioxide with water. 3 no2(g) + h2o(ℓ) −→ 2 hno3(ℓ) + no(g) if 85
Naya [18.7K]
The balanced equation for the above reaction is as follows;
3NO₂ + H₂O --> 2HNO₃ + NO
stoichiometry of NO₂ to NO is 3:1
molar volume is where 1 mol of any gas occupies a volume of 22.4 L
volume of gas is directly proportional to number of moles of gas.
therefore stoichiometry can be applied for volume as well.
volume ratio of NO₂ to NO is 3:1
volume of NO₂ reacted - 854 L
therefore volume of NO formed - 854 L /3 = 285 L
volume of NO formed - 285 L
8 0
3 years ago
Ca(OH)2 + 2 H2SO4 → CaSO4 + 2 H2O
Pie

Answer:

hope this helped

Calcium Hydroxide + Sulfuric Acid = Calcium Sulfate + Water

Explanation:

6 0
2 years ago
Read 2 more answers
As a child (with a mass of 35.0 kg) you take your 5.0-kg sled to Orchard Downs. If you are sliding down the hill on your sled, w
alukav5142 [94]

Velocity = 3.61 m/s

<h3>Further explanation</h3>

Given

mass of child = 35 kg

mass of sled = 5 kg

Kinetic energy = 260 J

Required

velocity

Solution

Energy because its motion is expressed as Kinetic energy (KE) which can be formulated as:

KE = 1/2.mv²

mass of object :

= mass child + mass sled

= 35 kg + 5 kg

= 40 kg

Input the value :

v²=KE : 1/2.m

v²= 260 : 1/2.40 kg

v²=13

v=3.61 m/s

3 0
3 years ago
How do you solve this problem
ad-work [718]

Answer: Volume of gas in the stomach, V = 0.0318L or 31.8mL

Explanation:

The number of moles of oxygen will remain constant even though the liquid oxygen will undergo a change of state to gaseous inside the person's stomach due to an increase in temperature.

<em>Number of moles of oxygen gas = mass/molar mass</em>

molar mass of oxygen gas = 32 g/mol

mass of oxygen gas = density * volume

mass of oxygen gas = 1.149 g/ml * 0.035 ml

mass of oxygen gas = 0.040215 g

Number of moles of oxygen gas = 0.0402 g/(32 g/mol)

Number of moles of oxygen gas = 0.00125 moles

<em>Using the ideal gas equation, PV=nRT</em>

where P = 1.0 atm, V = ?, n = 0.00125 moles, R = 0.082 L*atm/K*mol, T = (37 + 273)K = 310 K

<em>V = nRT/P</em>

V = (0.00125moles) * (0.082 L*atm/K*mol) * (310 K) / 1 atm

V = 0.0318L or 31.8mL

3 0
3 years ago
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