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Tatiana [17]
3 years ago
13

A 20 g granite boulder absorbs 300.2 Joules of energy from the Sun, resulting in its temperature

Chemistry
1 answer:
s344n2d4d5 [400]3 years ago
3 0

Answer:

19 °C

Explanation:

Step 1: Given and required data

  • Mass of granite (m): 20 g
  • Heat absorbed (Q): 300. 2 J
  • Specific heat capacity of granite (c): 0.790 J/g.°C

Step 2: Calculate the temperature change (ΔT)

We will use the following expression.

Q = c × m × ΔT

ΔT = Q/c × m

ΔT = 300.2 J/(0.790 J/g.°C) × 20 g = 19 °C

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Andreyy89
B.  He would be considered an Organic Chemist since Organic Chemistry is the study of Carbon and its compounds.
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3 years ago
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Calculate the percent ionization of nitrous acid in a solution that is 0.139 M in nitrous acid. The acid dissociation constant o
anzhelika [568]
Ok first, we have to create a balanced equation for the dissolution of nitrous acid.

HNO2 <-> H(+) + NO2(-)

Next, create an ICE table

           HNO2   <-->  H+        NO2-
[]i        0.139M          0M       0M
Δ[]      -x                   +x         +x
[]f        0.139-x          x           x

Then, using the concentration equation, you get

4.5x10^-4 = [H+][NO2-]/[HNO2]

4.5x10^-4 = x*x / .139 - x

However, because the Ka value for nitrous acid is lower than 10^-3, we can assume the amount it dissociates is negligable, 

assume 0.139-x ≈ 0.139

4.5x10^-4 = x^2/0.139

Then, we solve for x by first multiplying both sides by 0.139 and then taking the square root of both sides.

We get the final concentrations of [H+] and [NO2-] to be x, which equals 0.007M.

Then to find percent dissociation, you do final concentration/initial concentration.

0.007M/0.139M = .0503 or 

≈5.03% dissociation.
4 0
3 years ago
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In the presence of excess oxygen, methane gas burns in a constant-pressure system to yield carbon dioxide and water: CH4 (g) 2O2
Degger [83]

Answer:

The energy released will be -94.56 kJ or -94.6 kJ.

Explanation:

The molar mass of methane is 16g/mol

The given reaction is:

CH_{4}(g) + 2O_{2} (g) --> CO_{2} (g)+ 2H_{2}O(l)

the enthalpy of reaction is given as  ΔH = -890.0 kJ

This means that when one mole of methane undergoes combustion it gives this much of energy.

Now as given that the amount of methane combusted = 1.70g

The energy released will be:

=\frac{energy released by one moleXgiven mass}{molarmass} =\frac{-890X1.7}{16}= -94.56 kJ

7 0
3 years ago
Which of the following are correct for zero-order reactions?
GREYUIT [131]

Answer:

The answer is "Choice A and Choice B"

Explanation:

The Zero-Order reactions are usually found if a substrate, like a surface or even a catalyst, is penetrated also by reactants. Its success rate doesn't depend mostly on the amounts of the various reaction in this reaction.

Let the Rate = k

As \frac{dx}{dt} \ rate\ \  K_0 doesn't depend on reaction rate, a higher reaction rate does not intensify the reaction.

By the rate k_0 =\frac{dx}{dt}, the created based and the reaction rate is about the same.

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Which of the following statements incorrectly describes the assumptions of the kinetic molecular theory? Group of answer choices
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Sorry
J vre fdtnyscdvf. H Fr,I
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