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3 years ago

Geometry question plz help

Mathematics

1 answer:

Murrr4er [49]3 years ago

5 0

The surface area is 153.86

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Y=-4-x; domain = {-6, 2, 7} Find range plz

UNO [17]

Step-by-step explanation:

domain is the valid interval for the x (input) values for the function.

the range is the valid interval for the y (result) values of the function.

so, we have a function definition and a valid domain interval for x. we therefore try the x values and see what result values they create. and that defines the range.

x = -6

y = 4 - -6 = 4 + 6 = +10

x = 2

y = 4 - 2 = +2

x = 7

y = 4 - 7 = -3

we have therefore a range of {-3, 2, 10}

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2 years ago

Using a phone card to make a long distance call costs a flat fee of $0.57 plus $0.31 per minute starting with the first

aliina [53]

Answer:

it's d

Step-by-step explanation:

multiply 0.31 by the amount of minutes used (27) and add the flat fee to it.

0.31×27+(0.57)= 8.94

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2 years ago

Complete the following statement. Write sometimes, always, or never. A trapezoid____ has exactly one pair of parallel lines

AURORKA [14]

Answer:

always

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Jasmine knows that the area of a rectangle is the product of its base and height. Help her write an expression that represents t

Andrews [41]

Answer:

8b and 80

Step-by-step explanation:

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3 years ago

30 points!! What is the sum of the first six terms of the series? 48 - 12 + 3 - 0.75 +...

Lunna [17]

Answer:

The sum of the first six terms is 38.39

Step-by-step explanation:

This is a geometric sequence since the common difference between each term is $-\frac{1}{4}$

Thus, $r=-\frac{1}{4}$

To find the sum of first six terms, we need to find the fifth and sixth term of the sequence.

To find the fifth term:

The general form of geometric sequence is $a_{n}=a_{1} \cdot r^{n-1}$

To find the fifth term, substitute $n=5$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{5} &=(48) \cdot\left(-\frac{1}{4}\right)^{5-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{4} \\&=(48)\left(\frac{1}{256}\right) \\a_{5} &=0.1875\end{aligned}$

To find the sixth term, substitute $n=6$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{6} &=(48) \cdot\left(-\frac{1}{4}\right)^{6-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{5} \\&=(48)\left(-\frac{1}{1024}\right) \\a_{5} &=-0.046875\end{aligned}$

To find the sum of the first six terms:

The general formula to find Sn for $|r|$ is $S_{n}=\frac{a\left(1-r^{n}\right)}{1-r}$

$\begin{aligned}S_{6} &=\frac{48\left(1-\left(-\frac{1}{4}\right)^{6}\right)}{1-\left(-\frac{1}{4}\right)} \\&=\frac{48\left(1-\frac{1}{4096}\right)}{1+\frac{1}{4096}} \\&=\frac{48(0.95)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{47.9904}{5} \\&=38.39\end{aligned}$

Thus, the sum of first six terms is 38.39

5 0

2 years ago