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AlekseyPX
2 years ago
11

Identify the group of elements that does not readily combine with other elements.

Chemistry
1 answer:
7nadin3 [17]2 years ago
4 0
Noble gases
also known as Inert gases
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4. If the DNA nitrogen bases were TACCGGAT, how would the other half of
Illusion [34]

Answer:

<u>ATGGCCTA</u>

Explanation:

For this we have to keep in mind that we have a <u>specific relationship between the nitrogen bases</u>:

-) <u>When we have a T (thymine) we will have a bond with A (adenine) and viceversa</u>.

-) <u>When we have C (Cytosine) we will have a bond with G (Guanine) and viceversa</u>.

Therefore if we have: TACCGGAT. We have to put the corresponding nitrogen base, so:

TACCGGAT

<u>ATGGCCTA</u>

<u></u>

I hope it helps!

3 0
2 years ago
what is the formula used to find the heat energy for vaporization heat energy for fusion hrat energy for liquid
Alinara [238K]

Answer:

Use the formula q = m·ΔHv in which q = heat energy, m = mass, and ΔHv = heat of vaporization.

Explanation:

:)

8 0
2 years ago
what mass of carbon dioxide will be produced when 12.9 g of butane reacts with an excess of oxygen in the following reaction?
Nadya [2.5K]
39.1 gCO2
I think if that’s an option
3 0
2 years ago
How many molecules (not moles of nh3 are produced from 5.01×10?4 g of h2?
Irina-Kira [14]
2,02g     -------    6,02×10²³
5,01×10⁴g  ---    x

x=\frac{5,01*10^{4}g*6,02*10^{23}}{2,02g}=14,93*10^{27}

N₂         +        3H₂       ⇒           2NH₃
1mol      :        3mol        :           2mol
                       18,06×10²³  :       12,04×10²³
                       14,93×10²⁷  :        y

y=\frac{14,93*10^{27}*12,04*10^{23}}{18,06*10^{23}}\approx9,95*10^{27}
5 0
2 years ago
Does anyone know the answers for these
Alexeev081 [22]

Answer: 1. 0.045moles

2.  2.10 grams

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

1. \text{Number of moles of zinc nitrate}=\frac{8.51g}{189.36g/mol}=0.045moles

2. Mass of C_2H_4=moles\times {\text {Molar mass}}=0.075moles\times 28.05g/mol=2.10g

4 0
2 years ago
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