Answer:
0.256 L
Explanation:
We should use the following formula:
concentration (1) × volume (1) = concentration (2) × volume (2)
concentration (1) = 0.82 M NaOCl
volume (1) = ?
concentration (2) = 0.21 M NaOCl
volume (2) = 1 L
volume (1) = [concentration (2) × volume (2)] / concentration (1)
volume (1) = [0.21 / 1] / 0.82 = 0.256 L
Answer is: 79.8 grams of copper(II) sulfate.
N(CuSO₄) = 3.01·10²³; number of molecules.
n(CuSO₄) = N(CuSO₄) ÷ Na.
n(CuSO₄) = 3.01·10²³ ÷ 6.02·10²³ 1/mol.
n(CuSO₄) = 0.5 mol; amount of substance.
m(CuSO₄) = n(CuSO₄) · M(CuSO₄).
m(CuSO₄) = 0.5 mol · 159.6 g/mol.
m(CuSO₄) = 79.8 g; mass of substance.
M - molar mass.
The balance chemical equation is :
2HCL + Na2CO3 -----> 2NaCl + H2O + CO2
According to Question,
Given,
Molarity of HCL = 1.75 m
Sodium Carbonate (Na2CO3) = 0.100 m
For finding out the molarity,
c = n solute / Vsolution => n = c.Vsolution
nCO^2-3 = 0.100 mol L^-1 . 0.750 L = 0.0750 moles of CO^2-3
0.0750 moles of CO^2-3 . 2 moles H3O^+ / 1 mole CO^2-3
= 0.150 moles of H3O^+
As we have already know the molarity of HCL , we easily calculate what volumes by many moles.
c = nsolute / Vsolution => Vsolution = nsolute / c
VH3O^+ = 0.150 moles / 1.75 mol L^-1 = 0.0857 L
To know more about Molarity here :
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