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GaryK [48]
2 years ago
12

A solution contains 6.21 g of ethylene glycol dissolved in 25.0 g of water. If water has a boiling point elevation constant of 0

.512°C•kg/mol, what is the boiling point of the solution? (molar mass of ethylene glycol = 62.1 g/mol; boiling point of pure water = 100.00°C)
Chemistry
2 answers:
adell [148]2 years ago
7 0
The answer is D.) i just took the quiz
timurjin [86]2 years ago
5 0
Calculate first the number of moles of ethylene glycol by dividing the mass by the molar mass.
                           n = (6.21 g ethylene glycol) / 62.1 g/mol
                              n = 0.1 mol
Then, calculate the molality by dividing the number of moles by the mass of water (in kg).
                           m = 0.1 mol/ (0.025 kg) = 4m
Then, use the equation,
                       Tb,f = Tb,i + (kb)(m)
Substituting the known values,
                       Tb,f = 100°C + (0.512°C.kg/mol)(4 mol/kg)
                          <em>Tb,f = 102.048°C</em>
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ollegr [7]

Answer:

Difference in the potential energy of the reactants and products

Explanation:

 

The products have a lower potential energy than the reactants, and the sign of ΔH is negative. In an endothermic reaction, energy is absorbed. The products have a higher potential energy than the reactants, and the sign of ΔH is positive.

3 0
2 years ago
Given the speed of light as 3.0 × 108 m/s, calculate the wavelength of the electromagnetic radiation whose frequency is 7.5 × 10
arlik [135]
Wavelength= velocity/frequency
wavelength= (3.0 x 10^8m/s) / 7.5 x 10^12 Hz)
you can do the math
I am assuming u that 108 is 10^8 and the 1012 is 10^12
3 0
3 years ago
A vial containing radioactive selenium-75 has an activity of 3.0 mCi/mL. If 2.6 mCi are required for a leukemia test, how many m
oksian1 [2.3K]

Answer : The 866.66\mu L must be administered.

Solution :

As we are given that a vial containing radioactive selenium-75 has an activity of 3.0mCi/mL.

As, 3.0 mCi radioactive selenium-75 present in 1 ml

So, 2.6 mCi radioactive selenium-75 present in \frac{2.6mCi}{3.0mCi}\times 1ml=0.86666ml\times 1000=866.66\mu L

Conversion :

(1ml=1000\mu L)

Therefore, the 866.66\mu L must be administered.

4 0
2 years ago
Some growth regulators are useful to farmers and gardeners.<br> O True<br> O False
lisov135 [29]

Answer:

True

Explanation:

The first artificial use of a PGR was to stimulate the production of flowers on pineapple plants. They are now used widely in agriculture. Plant hormones are also used in turf management to reduce the need to mow, to suppress seedheads, and to suppress other types of grass.

3 0
3 years ago
During photosynthesis, how many moles of water (H₂O) are needed to produce 150 grams of glucose
Nuetrik [128]

During photosynthesis, 5 moles of water are needed to produce 150 grams of glucose. The correct option is D.

<h3>What is photosynthesis?</h3>

It is the process by which green plants and some other organisms use sunlight to synthesize nutrients from carbon dioxide and water.

  • Step 1: Write the balanced equation for photosynthesis.

6 CO₂ + 6 H₂O ⇒ C₆H₁₂O₆ + 6 O₂

  • Step 2: Convert 150 g of C₆H₁₂O₆ to moles.

The molar mass of C₆H₁₂O₆ is 180.16 g/mol.

150 g × 1 mol/180.16 g = 0.833 mol

  • Step 3: Calculate the moles of water required to form 0.833 moles of C₆H₁₂O₆

The molar ratio of H₂O to C₆H₁₂O₆ is 6:1.

0.833 mol C₆H₁₂O₆ × 6 mol H₂O/1 mol C₆H₁₂O₆ = 5.00 mol H₂O

During photosynthesis, 5 moles of water are needed to produce 150 grams of glucose. The correct option is D.

Learn more about photosynthesis here: brainly.com/question/3529377

#SPJ1

6 0
2 years ago
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