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Aleksandr [31]
3 years ago
10

Which name correctly classifies this triangle?

Mathematics
1 answer:
katrin [286]3 years ago
4 0
Isosceles triangle because it has two equal sides
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Wat the Pythagorean theorem
alexandr402 [8]

The Pythagorean theorem:

The theorem that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

<h2>The Pythagorean Theorem</h2><h3>Discoverer: Pythagoras</h3>

In mathematics, the Pythagorean theorem, or Pythagoras' theorem, is a fundamental relation in Euclidean geometry among the three sides of a right triangle. It states that the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides. These calculations were discovered just as a tool of the ancient civilization of Babylonians who used it to divide up farmland; this was roughly 1,000 years before the birth of the discoverer, Pythagoras, a Greek philosopher.

The formula comes like this:
a^2+b^2=c^2

5 0
1 year ago
5) What is the slope and the y-intercept of the line represented by the equation 4x + 3y - 12?
ale4655 [162]

Answer:

u[jkhpoi 9yuij ijiuyko yu yuoj kyujokyj[io jy jh[oyujokhk tkouykoj  tykkkjio nn uihjbnj kmvbhio mjghkobvjkoihjm nkligfj

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the function value. Round to four decimal places.
Aleks04 [339]
Convert to degrees

34°18' is the same as 34° 18' 0"

34° 18' 0" = 34° + 18'/60 + 0"/3600
= 34.3°

putting tan(34.3) into a calculator in degree mode

tan ( 34°18' )= tan(34.3) = 0.6822




3 0
2 years ago
HOW many right angles, obtuse angles and acute angles are there in this picture
ExtremeBDS [4]

Answer:

acute: 9

obtuse: 2

right: 2

Sorry if it wrong

6 0
2 years ago
The curve with equation y2 = 5x4 − x2 is called a kampyle of eudoxus. find an equation of the tangent line to this curve at the
Vesnalui [34]
To find the tangent line we will need the slope of the tangent at x=-1 (the x-coordinate of the point given). We find the slope by using the derivative of the curve.

Th curve given is y^{2} =5 x^{4} - x^{2} which can be solved for y by taking the root of both sides. We obtain y=(5 x^{4}- x^{2} ) ^{1/2}

We find the derivative using the chain rule. Bring down the exponent, keep the expression in the parenthesis, raise it to 1/2 - 1 and then take the derivative of what is inside.

y’=(1/2)(5 x^{4} - x^{2} )^{-1/2}(20 x^{3} -2x)

Next we evaluate this expression for x=-1 and obtain:
\frac{20(-1)^{3} -(2)(-1)}{2 \sqrt{5(-1 ^{4}-(-1 ^{2})  } }= \frac{-20+2}{2 \sqrt{5-1} }=-18/4=-9/2

So we are looking for a line through (-1,2) with slope equal to -9/2. We use y=mx+b with m=-9/2, x=-1 and y=2 to find b.

2=(-9/2)(-1)+b
2-(9/2)=b
b=-5/2

So the tangent line is given by y=(-9/2)x+(-5/2)

3 0
3 years ago
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