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2 years ago

The same amount of substance was added to four beakers of water. The treatments were placed in the chart.

Physics

2 answers:

tekilochka [14]2 years ago

7 0

A I think but my second choice is C

denis-greek [22]2 years ago

6 0

Answer:

C: Solutions W and Y have greater solubility than solutions X and Z.

Explanation:

Temperature and pressure affect the solubility of a solution as follows:

- the higher the pressure, the greater the solubility (because more pressure means more collisions between the molecules, so this improves the solubility)

- the higher the temperature, the greater the solubility (because higher temperature means higher kinetic energy of the molecules, so more collisions, and so this improves the solubility)

Therefore, considering these two factors, the solutions with greater solubility must be W (which has high pressure) and Y (which has high temperature).

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Calculate the constant acceleration a in g’s which the catapult of an aircraft carrier must provide to produce a launch velocity

goblinko [34]

The solution to the problem is as follows:

First, I'd convert 188 mi/hr to ft/s. You should end up with about ~275.7 ft/s.

So now write down all the values you know:

Vfinal = 275.7 ft/s

Vinitial = 0 ft/s

distance = 299ft

Now just plug in Vf, Vi and d to solve

Vf^2 = Vi^2 + 2 a d

BTW: That will give you the acceleration in ft/s^2. You can convert that to "g"s by dividing it by 32 since 1 g is 32 ft/s^2.

5 0

2 years ago

Lillle is running. She increases her initial speed of 30 km/h to 40 km/h so she

Alex777 [14]

Answer

$200km {h}^{ - 2}$

Explanation

$Acceleration = \frac{final \: \: \: velocity - initial \: \: velocity }{time} \\ = \frac{(40 - 30)km {h}^{ - 1} }{0.05h} \\ = \frac{10}{0.05} \\ = 200km {h}^{ - 2}$

Hope this helps you.

Let me know if you have any other questions :-):-)

6 0

3 years ago

Read 2 more answers

Suppose an object is launched from a point 320 feet above the earth with an initial velocity of 128 ft/sec upward, and the only

Ne4ueva [31]

Answer:

(a)Therefore the highest altitude attained by the object is =576 ft .

(b)Therefore the object takes 6 sec to fall to the ground.

Explanation:

Initial velocity: Initial velocity is a velocity from which an object starts to move.

u is usually used for notation of initial notation.

Final velocity: Final velocity is a velocity of an object after certain second from starting.

The final velocity is denoted by v.

Acceleration: The difference of final velocity and initial velocity per unit time

The S.I unit of acceleration is m/s².

(a)

Given that u= 128 ft\sec and g = 32 ft/sec².

At highest point the velocity of the object is 0 i.e v=0

Since the displacement is opposite to the gravity.

Therefore acceleration( a)= -g = -32 ft/sec².

To find the time this to happen we use the following formula

$v=u+at$

Here v=0

⇒0=128+(-32) t

⇒32t=128

⇒t = 4 sec

To determine the height we use the following formula

$s=ut+\frac{1}{2} at^2$

$\Rightarrow s= (128\times4)+\frac{1}{2}\times (-32) \times4^2$

⇒s= 256 ft

Therefore the highest altitude attained by the object is =(320+256)ft=576 ft .

(b)

At the highest point the velocity of the object is 0.

so u=0. a=g= 32 ft/sec² [ since the direction of gravity and the displacement are same] s= 576 ft

To determine the time to fall we use the following formula

$s=ut+\frac{1}{2} at^2$

$\Rightarrow 576 = (0\times t)+\frac{1}{2} \times 32 \times t^2$

$\Rightarrow 16\times t^2=576$

$\Rightarrow t^2=\frac{576}{16}$

$\Rightarrow t^2=36$

⇒t=6 sec

Therefore the object takes 6 sec to fall to the ground.

8 0

2 years ago

In a solid , the atoms are tightly locked in position an do not change posistion , true or false

attashe74 [19]

the answer is true because they're so close together that they can't move they can't slide past each other or anything

6 0

3 years ago

A fishing boat accidentally spills 3.0 barrels of diesel oil into the ocean. each barrel contains 42 gallons. if the oil film on

9966 [12]

Number of barrels are 3.0. Each barrel contains 42 gallons of oil. Thus, total volume of oil will be 42×3=126 gallons.

Converting gallons into m^{3}

1 gallon=0.00378 m^{3}

Thus, 126 gallons=0.4769 m^{3}

Thickness of oil film is 2.5\times 10^{2} nm, converting it into meters as follows:

1 nm=10^{-9} m

Thus,

2.5\times 10^{2} nm=1.5\times 10^{-7}m

Now, volume V of oil is related to area A and thickness T as follows:

V=A×T

rearranging,

A=\frac{V}{T}=\frac{0.4769 m^{3}}{2\times 10^{-7}m}=2.38\times 10^{6}m^{2}

Thus, square meters of oil will be 2.38\times 10^{6}m^{2}

7 0

3 years ago