Yes. Even greater. Air resistance or drag becomes harder the faster an object goes. This is why when cars reach their max speed they don't accelerate as fast, because they are pushing harder against the wind. If I take a tennis ball and shoot it down a bottomless pit, a 400 kph, the drag will slow the ball down till it reaches terminal velocity.
The correct is Reverberation. A reverberation is created when a sound or signal is reflected causing a large number of reflections to build up and then decay as the sound is absorbed by the surfaces of objects in the space – which could include furniture, people, and air.
Because it's the basis of how everything around you works
Answer:
Explanation:
Given
mass of saturated liquid water 
at
specific volume is
(From Table A-4,Saturated water Temperature table)



Final Volume 


Specific volume at this stage



Now we see the value and find the temperature it corresponds to specific volume at vapor stage in the table.


