A tire has a pressure of 325 kPa at 10°C.

Physics

2 answers:

musickatia [10]2 years ago

6 0

5 times that of initial pressure i.e 1625 kpa

alexdok [17]2 years ago

6 0

Original temperature = 10°C = 283 K .
New temperature = 50°C = 323 K.

Factor of temperature increase = 323/283 .

If volume is held constant, then pressure increases by the same factor.

(325 kPa) x (323/283) = 370.9... kPa (rounded)

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