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Karo-lina-s [1.5K]
3 years ago
12

A tire has a pressure of 325 kPa at 10°C.

Physics
2 answers:
musickatia [10]3 years ago
6 0
5 times that of initial pressure i.e 1625 kpa
alexdok [17]3 years ago
6 0
Original temperature  =  10°C  =  283 K .
New temperature  =  50°C  =  323 K.

Factor of temperature increase  =  323/283 .

If volume is held constant, then pressure increases by the same factor.

         (325 kPa) x (323/283)  =  370.9... kPa  (rounded)
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Q = 24 pC = 24 10⁻¹² C

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Q = 32 pC = 32 10⁻¹² C

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let's find the difference between these two fields

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