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Karo-lina-s [1.5K]
3 years ago
12

A tire has a pressure of 325 kPa at 10°C.

Physics
2 answers:
musickatia [10]3 years ago
6 0
5 times that of initial pressure i.e 1625 kpa
alexdok [17]3 years ago
6 0
Original temperature  =  10°C  =  283 K .
New temperature  =  50°C  =  323 K.

Factor of temperature increase  =  323/283 .

If volume is held constant, then pressure increases by the same factor.

         (325 kPa) x (323/283)  =  370.9... kPa  (rounded)
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The kinetic energy of a baseball is doubled by changing the speed of the baseball. By what factor has its speed changed? √ 2 v i
leonid [27]

Answer:

1/√2

Explanation:

Kinetic energy of a body is expressed as

KE = 1/2mv²

If it's KE is doubled

2KE = 1/2mv1² where v1 is the new speed when the kinetic energy is doubled

To know the value of the amount the velocity has changed, we will divide both equations

2KE/KE = (1/2mv²)/(1/2mv1²)

2 = v²/v1²

(v/v1)² = 2

v/v1 = √2

v1 = v/√2

v1 = 1/√2 × v

The new velocity has changed by

1/√2vinitial

7 0
3 years ago
Light of wavelength 630 nm is incident on a long, narrow slit. Determine the angular deflection of the first diffraction minimum
asambeis [7]

Answer:

a) 1.8°

b) 0.18°

c) 0.018°

Explanation:

Wavelength (λ) = 630nm = 630 *10^-9m

The equation that describes the angular deflection of a dark band is

Wsin(βm) = mλ

w = width of the single slit

λ = wavelength of the light

βm = angular deflection of the mth dark band.

a) In order to get the angular deflection of the first dark band for a slit with 0.02mm width, substitute w = 0.02mm = 0.02*10^-3 , m = 1 , λ= 630*10^-9

0.02*10^-3 sin(β1) = 1 * 630*10^-9

Sin(β1) = 630 * 10^-9 / 0.02*10^-3

Sin(β1) = 0.0315

β1 = Sin^-1(0.0315)

= 1.8°

b) substitute w = 0.2mm = 0.2*10^-3 , m = 1 , λ= 630*10^-9

0.2*10^-3 sin(β1) = 1 * 630*10^-9

Sin(β1) = 630 * 10^-9 / 0.2*10^-3

Sin(β1) = 0.00315

β1 = Sin^-1(0.00315)

= 0.18°

c) substitute w = 2mm = 2*10^-3 , m = 1 , λ= 630*10^-9

2*10^-3 sin(β1) = 1 * 630*10^-9

Sin(β1) = 630 * 10^-9 / 2*10^-3

Sin(β1) = 3.15*10^-4

β1 = Sin^-1(3.15*10^-4)

= 0.018°

6 0
3 years ago
At a wedding reception, you notice a child who looks like their mass is about 25 kg running across the dance floor then sliding
Vitek1552 [10]

Mass of the object m = 25 kg

Coefficient of friction Uk = 0.15

Frictional force Ff = Uk x F => Ff = Uk x m x g

Ff = 0.15 x 25 x 9.8

Frictional Force Ff = 36.75 N

4 0
3 years ago
Read 2 more answers
Emmett is lifting a box vertically. Which forces are necessary for calculating the total force?
GrogVix [38]

When Emmett is lifting a box vertically, the forces that must be added to calculate the total force are: the gravitational force, tension force(the force exerted by Emmett to the box and the force exerted by the box to Emmett), and air resistance force.

4 0
2 years ago
This is the si unit of current
skelet666 [1.2K]

Answer:

ampere

and it is denoted by A

3 0
2 years ago
Read 2 more answers
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