Answer:
a. Amplitude = 0.244 meters
b. Period = 1.62 seconds
c. Frequency = 0.6173 Hz
Explanation:
a.
With the position goes from 0.122 meters to -0.122 meters (negative because it is in the opposite side of the equilibrium point), the amplitude is the maximum value minus the minimum value:
Amplitude = 0.122 - (-0.122) = 0.122 + 0.122 = 0.244 meters
b.
The period is the amount of time the object takes to arrive in the same position again. So, if it takes 0.81 seconds to go to -0.122 m, it will take another 0.81 seconds to come back to 0.122 m, so the period is the sum of these two times:
Period = 0.81 + 0.81 + 1.62 seconds
c.
The frequency of the movement is the inverse of the period:
Frequency = 1 / Period
So if the period is 1.62 seconds, the frequency is:
Frequency = 1 / 1.62 = 0.6173 Hertz
Answer:
(a) Fₓ = 0 N
= 9.08 N
(b)
(a) Fₓ = 0 N
<u></u>
= 9.08 N
(c)
= 0 N
Fₓ = 9.08 N
Explanation:
The magnitude of the force will remain the same in each case, which is given as follows:
F = ma (Newton's Second Law)
where,
F = force = ?
m = mass = 4.54 kg
a = acceleration = 2 m/s²
Therefore,
F = (4.54 kg)(2 m/s²)
F = 9.08 N
Now, we come to each scenario:
(a)
Since the motion is in the vertical direction. Therefore the magnitude of the force in x-direction will be zero:
<u>Fₓ = 0 N</u>
For upward direction the force will be positive:
<u></u>
<u> = 9.08 N</u>
<u></u>
(b)
Since the motion is in the vertical direction. Therefore the magnitude of the force in x-direction will be zero:
<u>Fₓ = 0 N</u>
For upward direction the force will be negative:
<u></u>
<u> = - 9.08 N</u>
<u></u>
(c)
Since the motion is in the horizontal direction. Therefore the magnitude of the force in y-direction will be zero:
<u></u>
<u> = 0 N</u>
<u>Fₓ = 9.08 N</u>
I think it's d......... Good luck
The runner runs 8 meters per second or 28.8 kilometers per hour