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3 years ago

How was dance used in primitive cultures

Physics

1 answer:

ikadub [295]3 years ago

8 0

Can i get brainliest . i think it was used as a way of communication.

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List atleast to conditions that could cause the pressure inside a sealed container of gas to increase

hjlf

There are exactly three ways that could happen:

1). The container was heated, and the gas inside it got warmer.

2). Some part inside the container moved somehow, and made
      the inside volume smaller, so the gas got scrunched into a
      smaller space.

3). Somebody pumped some more gas into the container, so
      a greater amount of gas had to live in the same space.

8 0

3 years ago

When an unstable radioactive atom degrades, what happens to it?

malfutka [58]

it depends on the atom . but in some cases it may explode

7 0

3 years ago

what is the mass of vertical column of air that exerts pressure of 1 atm over a10m by 10m square surface

Oksana_A [137]

Answer:

$m=1.01\times 10^6\ kg$

Explanation:

Given that,

Pressure, P = 1 atm = 101325 Pa

Area of the square surface, A = 10² = 100 m²

We need to find the mass of vertical column of air. We know that, pressure is equal to the force acting per unit area. So,

$P=\dfrac{mg}{A}\\\\m=\dfrac{PA}{g}\\\\m=\dfrac{101325\times 10^2}{10}\\\\m=1.01\times 10^6\ kg$

So, the required mass of the vertical column of air is $1.01\times 10^6\ kg$ .

4 0

3 years ago

How long did Skylab orbit the earth?

maria [59]

Answer:

for abt 36 seconds

Explanation: cuz thats how long it was

4 0

3 years ago

A proton having an initial velvocity of 20.0i Mm/s enters a uniform magnetic field of magnitude 0.300 T with a direction perpend

Sonja [21]

The time interval for which the proton remains in the field is -

Δt = $$\frac{\pi R}{40}$ .

We have a proton entering a uniform magnetic field which is in a direction perpendicular to the proton's velocity.

We have to determine time interval during which the proton is in the field.

<h3>What is the magnitude of force on the charged particle moving in a uniform magnetic field?</h3>

The magnitude of force on the charged particle moving in a uniform magnetic field is given by -

F = qvB sinθ

According to the question, we have -

Entering Velocity (v) = 20 i m/s

Magnetic field intensity (B) = 0.3 T

Leaving velocity (u) = - 20 j m/s

Now -

The entering and leaving velocity vectors have 90 degrees difference between them. Therefore, only a quarter of distance of the complete circular path of radius 'R' is traced by the proton. Therefore -

d = $$\frac{2\pi r}{4}$ = $$\frac{\pi R}{2}$

Since, the radius of circular path is not given, we will assume it R.

Therefore, time for which proton remained in the field is -

t = $$\frac{\pi R}{2v} = \frac{\pi R}{40}$

Hence, the time interval for which the proton remains in the field is -

Δt = $$\frac{\pi R}{40}$

To solve more questions on Force on charged particle, visit the link below-

brainly.com/question/14597200

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6 0

2 years ago