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3 years ago

What is the relation of pressure of a liquid with its depth and density?

Physics

1 answer:

padilas [110]3 years ago

4 0

Answer:

★ Pressure and depth have a directly proportional relationship. This is due to the greater column of water that pushes down on an object submerged. Conversely, as objects are lifted, and the depth decreases, the pressure is reduced.

Explanation:

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3 years ago

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Answer:

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3 years ago

At its Ames Research Center, NASA uses its large "20-G" centrifuge to test the effects of very large accelerations ("hypergravit

Rzqust [24]

Answer:

32.9242311983 m/s

1.40506567727g

35.3405770759 rpm

Explanation:

v = Linear Velocity of the capsule

$a_c$ = Centripetal acceleration = $12.5g=12.5\times 9.81$

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l = Person's height = 2 m

Centripetal acceleration is given by

$a_c=\frac{v^2}{r}\\\Rightarrow v=a_cr\\\Rightarrow v=\sqrt{12.5\times 9.81\times 8.84}$

The linear speed of the capsule is 32.9242311983 m/s

The radius would be

$r=\sqrt{r^2+\dfrac{l^2}{4}}\\\Rightarrow r=\sqrt{8.84^2+\dfrac{2^2}{4}}\\\Rightarrow r=8.89638128679\ m$

The centripetal acceleration

$a_{c2}=\dfrac{32.9242311983^2}{8.89638128679\times 9.81}g\\\Rightarrow a_{c2}=12.4207805891g$

Change in acceleration from Pythagoras law

$a=\sqrt{a_{ch}^2-a_{c2}^2}\\\Rightarrow a=\sqrt{12.5^2g^2-12.4207805891^2g^2}\\\Rightarrow a=1.40506567727g$

The difference is 1.40506567727g

Velocity

$v=\omega r\\\Rightarrow v=2\pi Nr\\\Rightarrow N=\dfrac{v}{2\pi r}\\\Rightarrow N=\dfrac{32.9242311983}{2\pi 8.89638128679}\\\Rightarrow N=0.589009617932\ rev/s$

$N=0.589009617932\times 60=35.3405770759\ rpm$

The speed is 35.3405770759 rpm

4 0

3 years ago

40.

babunello [35]

Impact Craters would be the correct answer, I know this for a fact.

Please mark Brainliest!

6 0

3 years ago

What is the relation of pressure of a liquid with its depth and density?​

What is the relation of pressure of a liquid with its depth and density?