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Zolol [24]
3 years ago
6

Different masses are hung on a spring scale calibrated in newtons. The force exerted by gravity on 1.0 kg is shown in the image

below in newtons.
An image of a spring scale with a 1 kilogram weight attached. The scale reads 9.8 N.

What would be the force exerted by gravity on 6.5 kg?

6.5 N
9.8 N
64 N
98 N
Physics
2 answers:
Lunna [17]3 years ago
6 0
6.5 x 9.8
=63.7
so the answer is 64N
Arada [10]3 years ago
3 0

Answer:

F = 64 N

Explanation:

When 1 kg of weight attached with the spring, the scale reads 9.8 N. Weight of an object is the product of mass and acceleration due to gravity. Let F is the force exerted by gravity on 6.5 kg. It can be calculated as :

F=mg

F=6.5\ kg\times 9.8\ m/s^2

F = 63.7 N

or

F = 64 N

So, the force exerted by gravity on 6.5 kg is 64 N.

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Explanation:

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4 years ago
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Two facing surfaces of two large parallel conducting plates separated by 8.5 cm have uniform surface charge densities such that
elena-s [515]

Answer:

positive plate

E = 5.764 KV / m

W = 490eV or 7.85 * 10^-17 J

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Explanation:

part a

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part b

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E = 490 / 0.085 = 5.764 KV / m

Answer: Electric Field between the plates E = 5.764 KV / m

part c

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part d

Potential Energy of an electron gained:

E_p = m_e * g * d / (1.602*10^-19)

E_p =  9.109*10^-31* 9.81 * 0.085 / (1.602*10^-19)

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part e

Kinetic Energy of an electron gained:

W - E_p = E_k

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Answer: Kinetic Energy of an electron gained E_k = 490 eV

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vekshin1

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