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Zolol [24]
3 years ago
6

Different masses are hung on a spring scale calibrated in newtons. The force exerted by gravity on 1.0 kg is shown in the image

below in newtons.
An image of a spring scale with a 1 kilogram weight attached. The scale reads 9.8 N.

What would be the force exerted by gravity on 6.5 kg?

6.5 N
9.8 N
64 N
98 N
Physics
2 answers:
Lunna [17]3 years ago
6 0
6.5 x 9.8
=63.7
so the answer is 64N
Arada [10]3 years ago
3 0

Answer:

F = 64 N

Explanation:

When 1 kg of weight attached with the spring, the scale reads 9.8 N. Weight of an object is the product of mass and acceleration due to gravity. Let F is the force exerted by gravity on 6.5 kg. It can be calculated as :

F=mg

F=6.5\ kg\times 9.8\ m/s^2

F = 63.7 N

or

F = 64 N

So, the force exerted by gravity on 6.5 kg is 64 N.

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a truck is moving around a circular curve @ a uniform velocity of 13m/s. if the centifrical force on truck is 3,300N with truck
VMariaS [17]

<u>Answer</u>

81.94 m


<u>Explanation</u>

The centripetal force of an object moving in a circular path is given by:

F = mv²/r  Where m is the mass of the object, v is the constant velocity and r is the radius of the curve.

F = mv²/r

3,300 = (1600×13²)/r

3,300 = 270,400/r

r = 270,400/3,300

  = 81.94 m

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Then, let's find the cross-sectional area of the wire. Its radius is half the diameter,
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