All categories

2 years ago

PLS Help

Physics

1 answer:

ale4655 [162]2 years ago

6 0

Answer:

sport is an activity that involves movement and teamwork.

hobby is a personal interest that you enjoy doing often.

Explanation:

You might be interested in

Find a parametric representation for the surface. The plane through the origin that contains the vectors i - j and j - k

boyakko [2]

Answer:

parametric representation: x = u, y = v - u , z = - v

Explanation:

Given vectors :

i - j , j - k

represent the vector equation of the plane as:

r ( u, v ) = r₀ + <em>u</em>a + vb

where: r₀ = position vector

u and v = real numbers

a and b = nonparallel vectors

expressing the nonparallel vectors as :

a = i -j , b = j - k , r = ( x,y,z ) and r₀ = ( x₀, y₀, z₀ )

hence we can express vector equation of the plane as

r(u,v) = ( x₀ + u, y₀ - u + v, z₀ - v )

Finally the parametric representation of the surface through (0,0,0) i.e. origin = 0

( x, y , z ) = ( x₀ + u, y₀ - u + v, z₀ - v )

x = 0 + u ,

y = 0 - u + v

z = 0 - v

∴ parametric representation: x = u, y = v - u , z = - v

3 0

2 years ago

The length of a football field is closest to<br> (1) 1000 cm (3) 1000 km<br> (2) 1000 dm (4) 1000 mm

Sergeu [11.5K]

For this case, the first thing you should know is that the length of a football field is around 100 meters.

We must then look for a measure close to this value.

We have the following unit conversion:

1 meter = 10 decimeters

Applying the conversion we have:

$(1000 dm)*(\frac{1}{10} \frac{m}{dm}) = 100 m$

Therefore, the measure closest to a soccer field is:

1000 dm

Answer:

The length of a football field is closest to:

(2) 1000 dm

5 0

3 years ago

Read 2 more answers

A particle of charge Q is fixed at the origin of an xy coordinate system. At t = 0 a particle (m = 0.727 g, q = 2.73 µC is locat

Montano1993 [528]

Answer:

Q = 12.466μC

Explanation:

For the particle to execute a circular motion, the electrostatic force must be equal to the centripetal force:

$Fe = \frac{K*q*Q}{r^{2}} = \frac{m*V^{2}}{r}$

Solving for Q:

$Q = \frac{m*V^{2}*r}{K*q}$

Taking special care of all units, we can calculate the value of the charge:

Q = 12.466μC

5 0

2 years ago

A slice of cheese has a mass of 40 g and a volume of 23 cm^3. What is the density of the cheese in units of g/cm^3 and g/mL?

Mila [183]

The mathematical and proportional relationship between mL and $cm ^ 3$ said us that $1cm ^ 3$ is equivalent to 1mL.

If the density is considered as the amount of mass per unit volume we will have to

$\rho = \frac{m}{V}$

here,

m = mass

V = Volume

Replacing we have that

$\rho = \frac{40g}{23cm^3}$

$\rho = 1.739g/cm^3$

As $1mL = 1cm^3$ we have that the density in g/mL is,

$\rho = 1.739g/mL$

6 0

3 years ago

Spiders may "tune" strands of their webs to give an enhanced response at frequencies corresponding to the frequencies at which d

Bingel [31]

Answer:

0.0000167283525619 N

Explanation:

$\rho$ = Density of silk = 1300 kg/m³

d = Diameter = 0.002 mm

r = Radius = 0.001 mm

l = Length = 16 cm

f = Frequency = 200 Hz

Mass of the string is

$m=\rho V\\\Rightarrow m=\rho Al\\\Rightarrow m=1300\times \pi (0.001\times 10^{-3})^2\times 0.16\\\Rightarrow m=6.5345127195\times 10^{-10}\ kg$

Frequency is given by

$f=\dfrac{1}{2l}\sqrt{\dfrac{T}{m/l}}\\\Rightarrow T=4lf^2m\\\Rightarrow T=4\times 0.16\times 200^2\times 6.5345127195\times 10^{-10}\\\Rightarrow T=0.0000167283525619\ N$

The tension on the string is 0.0000167283525619 N

3 0

3 years ago