You first subtract the speed at which the man is moving (11 m/s) from the rate the boat is moving (12.4 m/s). Which equals 1.4, then divide it by 6 meters, as the man is moving relative to the boat.
It therefore equals 4.29 s
Answer:
1.97 × 10⁻¹⁸J
Explanation:
Charge of an electron q = -1.9 × 10⁻¹⁹C
Length of one side of the equilateral triangle at whose corners electrons are placed d = 3.5 × 10⁻¹⁰m
Coulomb constant k = 8.99 × 10⁹Nm²/C²
electrostatic potential = (3 kq²) / d
= (3 × 8.99 × 10⁹ × (-1.6 × 10⁻¹⁹)²) / 3.5 × 10⁻¹⁰
= 1.97 × 10¹⁸J
Answer choices ??? Or are there not any ?
True, I just learned this a week ago. Is this for Chemistry?