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aev [14]
2 years ago
9

PLS Help

Physics
1 answer:
ale4655 [162]2 years ago
6 0

Answer:

sport is an activity that involves movement and teamwork.

hobby is a personal interest that you enjoy doing often.

Explanation:

:)

You might be interested in
With what force will a car hit a tree if the car has a mass of 3,550 kg and it is accelerating at a rate of 2.5 m/s2 on a snowy
bekas [8.4K]

Answer:

<h2>8875 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 3550 × 2.5

We have the final answer as

<h3>8875 N</h3>

Hope this helps you

3 0
3 years ago
(a) Find the acceleration of B.<br>(b) Find the tensions, T1 and T2, in the strings.
Ann [662]

i believ that the answer would be

the acceleration of B is 0.2

6 0
3 years ago
Consider a hydrogen atom in the n = 1 state. The atom is placed in a uniform B field of magnitude 2.5 T. Calculate the energy di
dlinn [17]

Answer:

E=29\times 10^{-5}eV

Explanation:

For n-=1 state hydrogen energy level is split into three componets in the presence of external magnetic field. The energies are,

E^{+}=E+\mu B,

E^{-}=E-\mu B,

E^{0}=E

Here, E is the energy in the absence of electric field.

And

E^{+} and E^{-} are the highest and the lowest energies.

The difference of these energies

\Delta E=2\mu B

\mu=9.3\times 10^{-24}J/T is known as Bohr's magneton.

B=2.5 T,

Therefore,

\Delta E=2(9.3\times 10^{-24}J/T)\times 2.5 T\\\Delta E=46.5\times 10^{-24}J

Now,

Delta E=46.5\times 10^{-24}J(\frac{1eV}{1.6\times 10^{-9}J } )\\Delta E=29.05\times 10^{-5}eV\\Delta E\simeq29\times 10^{-5}eV

Therefore, the energy difference between highest and lowest energy levels in presence of magnetic field is E=29\times 10^{-5}eV

6 0
3 years ago
A 75-kg refrigerator is located on the 70th floor of a skyscraper (300meters a over the ground) What is the potential energy of
Nata [24]
Formula for potential energy is V=mgh, where m is mass in KG, g is earth acceleration (10 m/s^2), and h its height in meters. We know mass, acceleration is constant and also known, we know height also. Lets substitute
V=75*10*300=225000[J]=225[kJ] - its the answer
7 0
3 years ago
How much work is done on a satellite in a circular orbit about earth?
alexgriva [62]

Answer:

0 J

Explanation:

W = Work done on the satellite in circular orbit about earth by earth

F = Force on gravity on satellite by earth

d = displacement of the satellite

\theta = Angle between the force on gravity and displacement = 90

We know that, Work done is given as

W = F d Cos\theta\\W = F d Cos90\\W = F d (0)\\W = 0 J

3 0
3 years ago
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