Ask question

Ask question

All categories

Vladimir79 [104]

3 years ago

10

While exploring on your grandfathers farm, you find a layer of charcoal that might represent a campfire built by Native American

s. Explain how you could find the age of the charcoal layer?

1 answer:

Ierofanga [76]3 years ago

8 0

Carbon Dating would tell you the age of the charcoal

You might be interested in

WILL MARK BRAINLIEST

levacccp [35]

Okay so i think to calculate volume change you use the ideal gas law . this is pressure x volume = amount of substance x ideal gas constant x temperature. i honestly don’t know where to go from there but i hope this helped a bit :(

8 0

3 years ago

How many molecules are in 2.0 moles of oxygen gas

Dmitry [639]

Answer:

One mole of oxygen gas, which has the formula O2, has a mass of 32 g and contains 6.02 X 1023 molecules of oxygen but 12.04 X 1023 (2 X 6.02 X 1023) atoms, because each molecule of oxygen contains two oxygen atoms.

Explanation:

3 0

3 years ago

Read 2 more answers

What is a possible charge of an anion?<br><br> +3<br><br><br> -2<br><br><br> 0<br><br><br> +1

Whitepunk [10]

An Anion is negativity charged.
-2

4 0

3 years ago

Read 2 more answers

Which of the following summarizes photosynthesis?

Dmitry [639]

Carbon dioxide + water → glucose + oxygen + water

6 0

4 years ago

The rate law for the reaction 2A + B →C is –rA= kACA2CBwithkA= 25 (L/mol)2sec. What arekBandkC?

givi [52]

Explanation:

The given reaction equation is as follows.

$2A + B \rightarrow C$

So, rate constants for different reactants and products written as follows.

$\frac{-k_{A}}{\text{stoichiometric coefficient of A}} = \frac{-k_{B}}{\text{stoichiometric coefficient of B}} = \frac{k_{C}}{\text{stoichiometric coefficient of C}}$

As per the reaction equation, the stoichiometric coefficients of reactants and products are as follows.

A = -2

B = -1

C = 1

Therefore,

$\frac{-k_{A}}{\text{stoichiometric coefficient of A}} = \frac{-k_{B}}{\text{stoichiometric coefficient of B}} = \frac{k_{C}}{\text{stoichiometric coefficient of C}}$

$\frac{-k_{A}}{-2} = \frac{-k_{B}}{-1} = \frac{k_{C}}{1}$

$\frac{-k_{A}}{-2} = k_{B} = k_{C}$

Hence, $k_{B} = k_{C}$ = $\frac{25}{2} (L/mol)^{2}$

= 12.5 $(L/mol)^{2}$

Thus, we can conclude that $k_{B}$ and $k_{C}$ are 12.5 $(L/mol)^{2}$ .

5 0

4 years ago