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3 years ago

A large body of air hats has similar properties of a temperature and moisture is a

Physics

1 answer:

irina1246 [14]3 years ago

6 0

A large body of air hats has similar properties of a temperature and moisture is an air mass.

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An 8.2 kg object accelerates at 8.0 m/s^2. What is the acceleration?

ZanzabumX [31]

Answer:

8.0m/s²

Explanation:

meters per second squared is a unit of acceleration so 8.0m/s² is the answer

6 0

2 years ago

1. The choice of materials for an exciting playground slide should __________.

gavmur [86]

have a large coefficient of kinetic friction between cloth and the slide material
40(0.3+0.5)=40(0.8)=32N
F-applied=Wbook/μk
When the tire is locked, the frictional force is greater but the car cannot be steered

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2 years ago

Read 2 more answers

A skier leaves the horizontal end of a ramp with a velocity of 25.0 m/s and lands 70.0 m from the base of the ramp. How high is

Valentin [98]

Answer:

The end of the ramp is 38.416 m high

Explanation:

Horizontal Motion

When an object is thrown horizontally with an initial speed v and from a height h, it follows a curved path ruled by gravity.

The maximum horizontal distance traveled by the object can be calculated as follows:

$\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}$

If the maximum horizontal distance is known, we can solve the above equation for h:

$\displaystyle h=\frac {d^2g}{2v^2}$

The skier initiates the horizontal motion at v=25 m/s and lands at a distance d=70 m from the base of the ramp. The height is now calculated:

$\displaystyle h=\frac {70^2\cdot 9.8}{2\cdot 25^2}$

$\displaystyle h=\frac {4900\cdot 9.8}{2\cdot 625}$

h= 38.416 m

The end of the ramp is 38.416 m high

8 0

2 years ago

Suppose we hang a heavy ball with a mass 13 kg (so the weight is ) from a steel wire 3.9 m long that is 3.1 mm in diameter (radi

Katena32 [7]

Answer:

1.635×10^-3m

Explanation:

Young modulus is the ratio of the tensile stress of a material to its tensile strain.

Young modulus = Tensile stress/tensile strain

Tensile stress = Force/Area

Given force = 130N

Area = Πr² = Π×(1.55×10^-3)²

Area = 4.87×10^-6m²

Tensile stress = 130/4.87×10^-6 = 8.39×10^7N/m²

Tensile strain = extension/original length

Tensile strain = e/3.9

Substituting in the young modulus formula given young modulus to be 2×10¹¹N/m²

2×10¹¹N/m² = 8.39×10^7/{e/3.9)}

2×10¹¹ = (8.39×10^7×3.9)/e

2×10¹¹e = 3.27×10^8

e = 3.27×10^8/2×10¹¹

e = 1.635×10^-3m

The stretch of the steel wire will be

1.635×10^-3m

7 0

3 years ago

Wha is amplitde in sound

NemiM [27]

Answer:

The number of molecules displaced in a vibration makes the amplitude of a sound.

7 0

3 years ago