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3 years ago

A large body of air hats has similar properties of a temperature and moisture is a

Physics

1 answer:

irina1246 [14]3 years ago

6 0

<span>A large body of air hats has similar properties of a temperature and moisture is an air mass.</span>

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Can someone help me. PPPPPLLLLLLLLZZZ!!!!!!!!!!

Solnce55 [7]

Answer:

The answer would be d because of were the bolt is it has to reset after using it.

8 0

3 years ago

1500 kg wrecking ball traveling at a speed of 3.5 m/s hits a wall that does not crumble but is pushed back 75 cm. If the wreckin

Rudiy27

Answer:

The size of the force that pushes the wall is 12,250 N.

Explanation:

Given;

mass of the wrecking ball, m = 1500 kg

speed of the wrecking ball, v = 3.5 m/s

distance the ball moved the wall, d = 75 cm = 0.75 m

Apply the principle of work-energy theorem;

Kinetic energy of the wrecking ball = work done by the ball on the wall

¹/₂mv² = F x d

where;

F is the size of the force that pushes the wall

¹/₂mv² = F x d

¹/₂ x 1500 x 3.5² = F x 0.75

9187.5 = 0.75F

F = 9187.5 / 0.75

F = 12,250 N

Therefore, the size of the force that pushes the wall is 12,250 N.

7 0

2 years ago

A person jogs 4.o km in 32 minutes then 2.0 km in 22 minutes and finally 1.0 km in 16 minutes. What is the joggers average speed

AlladinOne [14]

Average speed = distance travelled / time used

6 0

2 years ago

An object of mass, m1 with a velocity, v1 collides with another object at rest (v2 = 0) with a mass, m2. After the collision, m1

goblinko [34]

Answer:

$v"_{1} = v_{1} tan$ Θ

$v^{"} _{2} = \frac{m_{1}v_{1}}{m_{2}cos}$ Θ

Θ = $tan^{-1}(\frac{v^{"} _{1} }{v_{1} } )$

Explanation:

Applying the law of conservation of momentum, we have:

Δ $p_{x = 0}$

$p_{x} = p"_{x}$

$m_{1}v_{1} = m_{2}v"_{2} cos$ Θ (Equation 1)

Δ $p_{y} = 0$

$p_{y} = p"_{y}$

$0 = m_{1} v"_{1} - m_{2} v"_{2} sin$ Θ (Equation 2)

From Equation 1:

$v"_{2} = \frac{m_{1}v_{1}}{m_{2}cos}$ Θ

From Equation 2:

$m_{2} v"_{2}$ sinΘ = $m_{1} v_{1}$

$v"_{1} = \frac{m_{2} v"_{2}sinΘ}{m_{1} }$

Replacing Equation 3 in Equation 4:

$v"_{1}=\frac{m_{2}\frac{m_{1}v_{1}}{m_{2}cosΘ}sinΘ}{m_{1}}$

$v"_{1}=v_{1}\frac{sinΘ}{cosΘ}$

$v"_{1}=v_{1}tan$ Θ (Equation 5)

And we found Θ from the Equation 5:

tanΘ= $\frac{v"_{1}}{v_{1}}$

Θ= $tan^{-1}(\frac{v"_{1}}{v_{1}})$

7 0

3 years ago

Wave travelling along right with speed of 0. 5 m/s time 4 second point p

Soloha48 [4]

The wavelength of the wave which is travelling along right with speed of 0. 5 m/s time 4 second point is 2.

<h3>What is the speed of wave?</h3>

Speed of wave is the rate by which the wave travels. It can be described as the distance cover by the crest or thrust of it per unit of time. It can be calculated with the following formula,

$v=f\times\lambda$

Here, (f) is the frequency and (λ) is the wavelength.

The frequency is inverse of time. Thus, the value of frequency in time t is,

$f=\dfrac{1}{t}\\f=\dfrac{1}{4}\\f=0.25$

The speed of the wave is 0.5 m/s. Put the values in the formula,

$v=f\times\lambda\\0.5=0.25\times\lambda\\\lambda=\dfrac{0.5}{0.25}\\\lambda=2$

Thus, the wavelength of the wave which is travelling along right with speed of 0. 5 m/s time 4 second point is 2.

Learn more about the speed of wave here;

brainly.com/question/12215474

#SPJ4

5 0

1 year ago