Answer:
t = 8 s
Explanation:
In order to find the time taken by the dragster we will use equations of motion. Here, we will use second equation of motion:
s = Vi t + (1/2)at²
where,
s = distance covered = 320 m
Vi = Initial Velocity = 0 m/s (Since, dragster starts from rest)
t = time taken = ?
a = acceleration of dragster = 10 m/s²
Therefore,
320 m = (0 m/s)t + (1/2)(10 m/s²)t²
t² = (320 m)(2)/(10 m/s²)
t = √(64 s²)
<u>t = 8 s</u>
Answer:
Explanation:
Kinematics equation for first Object:
but:
The initial velocity is zero
it reach the water at in instant, t1, y(t)=0:
Kinematics equation for the second Object:
The initial velocity is zero
but:
it reach the water at in instant, t2, y(t)=0. If the second object is thrown 1s later, t2=t1-1=1.02s
The velocity is negative, because the object is thrown downwards
Answer:
It will remain same i.e. 4.0 Hz
Explanation:
In a mass-and-spring system, the frequency depends upon the mass (m) and the spring constant (k).
Since, the frequency does not depend on the initial displacement of the mass, the frequency would remain the same i.e. 4.0 Hz.
Answer:
V = IR
Explanation:
Voltage is denoted by V, current is denoted by I and resistance is denoted by R. Voltage is the difference of electric potential between two points. Current is the measure of the rate of flow of electric charge. Resistance is a measure how a device reduces the current flow through itself.
The three properties are related to each other as per the Ohm's law which states that voltage and current are directly proportional to each other, it can be denoted as
Voltage (V) = Current(I) X Resistance(R).
So here is my answer. Given that the electric field in <span>a 3.0mm×3.0mm square aluminum wire is 1.0×10−2 V/m, this is how we find the current in the wire.
</span><span>First, we take the distance as 3mm or 0.003m. Using the formula E=V/d, where d is distance, v voltage and E electric field strength, we make V the subject, being V=Ed or 2.2*10^-2*0.003=6.6*10^-5V
</span>Hope this answers your question.
