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Flauer [41]
4 years ago
7

A large body of air hats has similar properties of a temperature and moisture is a

Physics
1 answer:
irina1246 [14]4 years ago
6 0
<span>A large body of air hats has similar properties of a temperature and moisture is an air mass.</span>
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What is the difference between heat and temperature
Tasya [4]
Temperature is the measurement system we use to measure the heat
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3 years ago
Earth travels fastest in January and slowest in July. What is the most likely explanation for this?
Keith_Richards [23]

Answer:

Earth is nearest the Sun in July and farthest away in July.

Explanation:

3 0
3 years ago
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Which statement describes the kinetic energy of a particle?
worty [1.4K]
Kinetic energy has nothing to do with anything other than motion of the particle.
When a particle with velocity v collides another particle(suppose it is at rest for simplication), assuming that there is perfectly elastic collision between them, the velocity of particle which was at rest becomes mv/M ( assuming mass of particle in motion to be m and at rest to be M) from convervation of linear momentum. And all this transfer of energy happens in a fraction of seconds which is not visible to naked eyes.

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A solution that has a high concentration of hydrogen ions has what type of pH?
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I believe the answer is A.
4 0
4 years ago
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Calculate the kinetic energy that the earth has because of (a) its rotation about its own axis and (b) its motion around the sun
Dominik [7]

Answer:

a. K_{Axis}=2.574x10^{29}J

b. K_{Orbit}=2.6577x10^{33}J

Explanation:

K_{Axis}=\frac{1}{2}I*w^2

I_{Sphere}=\frac{2}{5}*m*r^2

w=\frac{2\pi }{T} , T=24hrs*\frac{3600s}{1hr} =86400s

radius earth = 6371 km

mass earth = 5,972*10^24 kg

a.

K_{Axis}=\frac{1}{2}*\frac{2}{5}*m*r^2*(\frac{2\pi}{T})^2

K_{axis}=\frac{4\pi^2}{5}*5.98x10^{24}kg*(6.38x10^6m)^2*(\frac{1}{86400s})^2

K_{Axis}=2.574x10^{29}J

b.

T=1year*\frac{365day}{1year}*\frac{24hr}{1day}*\frac{3600s}{1hr}=31536000s

K_{Orbit}=\frac{1}{2}*I*w

I=m*r^2

K_{Orbit}=\frac{1}{2}*m*r^2*(\frac{2\pi}{T})^2

K_{Orbit}=\frac{4\pi^2}{5}*5.98x10^{24}*6.38x10^6m*(\frac{1}{31.536x10^6s})^2

K_{Orbit}=2.6577x10^{33}J

4 0
4 years ago
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