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3 years ago

The autotorium has 250 seats. 215 seats were sold for the next showing. What percent of seats are empty?

Mathematics

1 answer:

Mazyrski [523]3 years ago

8 0

Answer:

14%

Step-by-step explanation:

Well, 250-215 is 35 and 35 divided by 250 (That's how you get percent, since it would be 35\250 you divide,) is .14, which is your percent.

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I think is C but I’m not really sure

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3 years ago

A poll was conducted by a home mortgage company regarding home ownership in the United States. The company polled 1,488 American

____ [38]

If the sample size is 1488 and confidence interval of 99% then the margin of error is 0.03088.

Given sample size of 1488, percentage of those polled own a home be 69% and confidence level be 99%.

We are required to find the approximate margin of error.

Margin of error is the difference between calculated values and real values.

n=1488

p=0.69

Margin of error=z* $\sqrt{p(1-p)/n}$

Z score when confidence level is 99%=2.576.

Margin of error=2.576* $\sqrt{0.69(1-0.69)/1488}$

=2.576* $\sqrt{(0.69*0.31)/1488}$

=2.576* $\sqrt{0.2139/1488}$

=2.576* $\sqrt{0.0001437}$

=2.576*0.01198

=0.03088

Hence if the sample size is 1488 and confidence interval of 99% then the margin of error is 0.03088.

Learn more about margin of error at brainly.com/question/10218601

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2 years ago

Let f be defined by the function f(x) = 1/(x^2+9)

riadik2000 [5.3K]

(a)

$\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}$

Substitute x = 3 tan(t ) and dx = 3 sec²(t ) dt :

$\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt$

$=\displaystyle \frac13 \lim_{b\to\infty}\left(\arctan\left(\frac b3\right)-\arctan(1)\right)=\boxed{\dfrac\pi{12}}$

(b) The series

$\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}$

converges by comparison to the convergent p-series,

$\displaystyle\sum_{n=3}^\infty\frac1{n^2}$

$\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}$

converges absolutely, since

$\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}$

That is, ∑ (-1)ⁿ (n ² + 9)/eⁿ converges absolutely because ∑ |(-1)ⁿ (n ² + 9)/eⁿ| = ∑ (n ² + 9)/eⁿ in turn converges by comparison to a geometric series.

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3 years ago

Line p has a slope of 6/7. Line q is perpendicular to p . What is the slope of line q

Serjik [45]

Answer:

The slope of line q is -7/6

Step-by-step explanation:

To find the slope of a perpendicular line, you need to find the opposite reciprocal. So, flip the fraction (7/6) and then take the opposite, (-7/6).

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allochka39001 [22]

Answer:

The constant of variation is $1.50

Step-by-step explanation:

Given

Point 1 (1,2)

Point 2 (5,8)

Required