The autotorium has 250 seats. 215 seats were sold for the next showing. What percent of seats are empty?
1 answer:
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<span>We have the yearly cost in dollars y at a video game arcade based on total game tokens purchased 
. So we know that:
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Then we can study this problem by using the graph in the figure below. We know that if there's no any purchase, the yearly cost for a member will be $60 and for a nonmember there will not be any cost. From this, we can affirm that the cost of membership is equal to $60.
On the other hand, both members and nonmembers will pay the same price on the total game tokens purchased, this is true because of the same slope that members and nonmembers have in the equations.</span>
</span>
</span>
</span><span>
Then we can study this problem by using the graph in the figure below. We know that if there's no any purchase, the yearly cost for a member will be $60 and for a nonmember there will not be any cost. From this, we can affirm that the cost of membership is equal to $60.
On the other hand, both members and nonmembers will pay the same price on the total game tokens purchased, this is true because of the same slope that members and nonmembers have in the equations.</span>
Answer:
The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 10 - 1 = 9
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of . So we have T = 3.25
The margin of error is:
M = T*s = 3.25*25 = 81
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 12,556 - 81 = 12,475 pounds
The upper end of the interval is the sample mean added to M. So it is 12,556 + 81 = 12,637 pounds.
The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.